题目链接:http://ac.jobdu.com/problem.php?pid=1005

详解链接:https://github.com/zpfbuaa/JobduInCPlusPlus

参考代码:

//
// 1005 Graduate Admission.cpp
// Jobdu
//
// Created by PengFei_Zheng on 27/04/2017.
// Copyright © 2017 PengFei_Zheng. All rights reserved.
// #include <stdio.h>
#include <iostream>
#include <algorithm>
#include <string.h>
#include <cmath>
#define CHOOSE 6
#define MAX_SIZE 40001
#define SCHOOL 101 using namespace std; int n, m, k ; struct Apply{
int ge;
int gi;
double gf;
int choose[CHOOSE];
int id;
bool operator < (const Apply &A) const{
if(gf != A.gf){
return gf > A.gf;
}
else if(ge != A.ge){
return ge > A.ge;
}
else {
return ge > A.ge;
}
}
};
struct School{
int quota;
int realNum;
int appid[MAX_SIZE];
}; Apply apply[MAX_SIZE];
School school[SCHOOL]; int main(){
while(scanf("%d%d%d",&n,&m,&k)!=EOF){ for(int i = ; i < m ; i++){
scanf("%d",&school[i].quota);
school[i].realNum=;
}
for(int i = ; i < n ; i++){
scanf("%d%d",&apply[i].ge,&apply[i].gi); apply[i].gf=(double)(apply[i].ge+apply[i].gi)/2.0; for(int j = ; j < k ; j++){
scanf("%d",&apply[i].choose[j]);
}
apply[i].id=i;
}
sort(apply,apply+n);
int sid;
for(int i = ; i < n ; i++){
for(int j = ; j < k ; j++){
sid = apply[i].choose[j];
if(school[sid].quota > ){
school[sid].appid[school[sid].realNum] = i;
school[sid].realNum++;
school[sid].quota--;
break;
}
else{
int lastid = school[sid].appid[school[sid].realNum-];
if(apply[i].gf == apply[lastid].gf && apply[i].ge == apply[lastid].ge){
school[sid].appid[school[sid].realNum]=i;
school[sid].realNum++;
school[sid].quota--;
break;
}
}
}
} for(int i = ; i < m ; i++){
for(int j = ; j < school[i].realNum ; j++){
school[i].appid[j] = apply[school[i].appid[j]].id;
}
} for(int i = ; i < m ; i++){
if(school[i].realNum==){
printf("\n");
}
else if(school[i].realNum==){
printf("%d\n",school[i].appid[]);
}
else{
sort(school[i].appid,school[i].appid+school[i].realNum);
bool first = true;
for(int j = ; j < school[i].realNum ; j++){
if(first==true){
first = false;
}
else{
printf(" ");
}
printf("%d",school[i].appid[j]);
}
printf("\n");
}
}
}
return ;
}
/**************************************************************
Problem: 1005
User: zpfbuaa
Language: C++
Result: Accepted
Time:0 ms
Memory:19180 kb
****************************************************************/

题目1005:Graduate Admission(录取算法)的更多相关文章

  1. 题目1005:Graduate Admission

    题目1005:Graduate Admission 时间限制:1 秒 内存限制:32 兆 特殊判题:否 题目描述: It is said that in 2011, there are about 1 ...

  2. PAT 1080 Graduate Admission[排序][难]

    1080 Graduate Admission(30 分) It is said that in 2011, there are about 100 graduate schools ready to ...

  3. PAT_A1080#Graduate Admission

    Source: PAT A1080 Graduate Admission (30 分) Description: It is said that in 2011, there are about 10 ...

  4. PAT-1080 Graduate Admission (结构体排序)

    1080. Graduate Admission It is said that in 2013, there were about 100 graduate schools ready to pro ...

  5. 1080 Graduate Admission——PAT甲级真题

    1080 Graduate Admission--PAT甲级练习题 It is said that in 2013, there were about 100 graduate schools rea ...

  6. pat 甲级 1080. Graduate Admission (30)

    1080. Graduate Admission (30) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue It ...

  7. PAT 甲级 1080 Graduate Admission (30 分) (简单,结构体排序模拟)

    1080 Graduate Admission (30 分)   It is said that in 2011, there are about 100 graduate schools ready ...

  8. pat1080. Graduate Admission (30)

    1080. Graduate Admission (30) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue It ...

  9. 题目1005:Graduate Admission(结构体排序)

    问题来源 http://ac.jobdu.com/problem.php?pid=1005 问题描述 这道题理解题意有些麻烦,多看几遍先理解题意再说.每个学生有自己的三个成绩,一个编号,以及一个志愿列 ...

随机推荐

  1. 多个IoC容器适配器设计及性能测试(Castle.Windsor Autofac Spring.Core)

    [转]多个IoC容器适配器设计及性能测试和容器选择 1. 采用的IoC容器和版本 Autofac.2.6.3.862 Castle.Windsor.3.1.0 Spring.Core.2.0.0 2. ...

  2. ubuntu 16.04使用软件中心升级软件后桌面显示空白

    转载:http://www.jb51.net/os/Ubuntu/472560.html 每次在ubuntu Software里进行Updates后(或者直接关机后),重启电脑后,桌面显示空白 解决办 ...

  3. lakala反欺诈建模实际应用代码GBDT监督学习

    /** * Created by lkl on 2018/1/16. */ import org.apache.spark.mllib.evaluation.BinaryClassificationM ...

  4. js粘贴事件paste简单解析及遇到的坑

    在用户执行粘贴操作的时候,js能够获得剪切板的内容,本文讨论一下这个问题. 目前只有Chrome支持获取剪切板中的图片数据.还好需要这个功能的产品目前只支持Chrome和Safari,一些Chrome ...

  5. Lua基础语法讲解

    Lua 是什么? Lua 是一种轻量小巧的脚本语言,用标准C语言编写并以源代码形式开放, 其设计目的是为了嵌入应用程序中,从而为应用程序提供灵活的扩展和定制功能. Lua 是巴西里约热内卢天主教大学( ...

  6. mysql日期问题

    1.在java中,在当前时间的基础上增加30天.Date d = new Date();   SimpleDateFormat df = new SimpleDateFormat("yyyy ...

  7. android手机内的通讯录数据库

    今天看了一下 android手机内的通讯录数据库,简单的汇总了一下. 数据库见附件中的contacts2.db , 里面一共有40个表,34个视图,很庞大,挑几个重点的看一下. 1.表Raw_cont ...

  8. geoserver REST使用

    1.部署一个简单的测试环境 测试geoserver REST接口,我们可使用python来测试,很方便.需要下载包: python,http://python.org/.我下载的是Python27版本 ...

  9. js中判断浏览器版本

    var ai = { ovb: { /** * 该对象用于判断系统,系统版本,浏览器,苹果设备等等功能.ovb是单词 Os Version Browser 的头字母缩写. */ _version_va ...

  10. 分享一个有趣的代码,调用电脑中的api语音

    在文本文件中输入如下代码: set objTTS = CreateObject("sapi.spvoice") objTTS.speak("为啥我对象这么闹呢?" ...