其实就是链表求交:

 #include <iostream>
#include <cstdio>
#include <cstdlib>
#include <unordered_map> using namespace std; class Node {
public:
Node() : data(), next() {}
char data;
int next;
}; void print_list(unordered_map<int, Node*>& mem, int head) {
int cur = head;
while (cur != -) {
cout<<mem[cur]->data<<" ";
cur = mem[cur]->next;
}
cout<<endl;
}; int step_list(unordered_map<int, Node*>& mem, int from, int n) {
if (n < ) return -;
int cur = from;
while (cur != -) {
if (n == ) {
break;
}
cur = mem[cur]->next;
n--;
}
return cur;
} int count_list(unordered_map<int, Node*>& mem, int from) {
if (from < ) return ;
int cur = from;
int cnt = ;
while (cur != -) {
cur = mem[cur]->next;
cnt++;
}
return cnt;
} int main() {
int head_a, head_b;
int n; unordered_map<int, Node*> mem; cin>>head_a>>head_b>>n; for (int i=; i<n; i++) {
int addr;
Node* np = new Node();
scanf("%d %c %d", &addr, &(np->data), &(np->next));
mem.insert(make_pair(addr, np));
} int cnt_a = count_list(mem, head_a);
int cnt_b = count_list(mem, head_b); int cnt_diff = cnt_a - cnt_b;
int head_long = head_a;
int head_short = head_b;
if (cnt_diff < ) {
cnt_diff = -cnt_diff;
head_long = head_b;
head_short= head_a;
} head_long = step_list(mem, head_long, cnt_diff); while (head_long != head_short) {
head_long = mem[head_long]->next;
head_short= mem[head_short]->next;
}
if (head_long < ) {
printf("-1\n");
} else {
printf("%05d\n", head_long);
}
system("pause");
return ;
}

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