Out of Sorts II
问题 E: Out of Sorts II
时间限制: 1 Sec 内存限制: 128 MB
提交: 68 解决: 4
[提交] [状态] [讨论版] [命题人:]
题目描述
Her favorite algorithm thus far is "bubble sort". Here is Bessie's initial implementation, in cow-code, for sorting an array A of length N.
sorted = false
while (not sorted):
sorted = true
moo
for i = 0 to N-2:
if A[i+1] < A[i]:
swap A[i], A[i+1]
sorted = false
Apparently, the "moo" command in cow-code does nothing more than print out "moo". Strangely, Bessie seems to insist on including it at various points in her code.
After testing her code on several arrays, Bessie learns an interesting observation: while large elements can be pulled to the end of the array very quickly, it can take small elements a very long time to "bubble" to the front of the array (she suspects this is how the algorithm gets its name). In order to try and alleviate this problem, Bessie tries to modify her code so that it scans forward and then backward in each iteration of the main loop, so that both large and small elements have a chance to be pulled long distances in each iteration of the main loop. Her code now looks like this:
sorted = false
while (not sorted):
sorted = true
moo
for i = 0 to N-2:
if A[i+1] < A[i]:
swap A[i], A[i+1]
for i = N-2 downto 0:
if A[i+1] < A[i]:
swap A[i], A[i+1]
for i = 0 to N-2:
if A[i+1] < A[i]:
sorted = false
Given an input array, please predict how many times "moo" will be printed by Bessie's modified code.
输入
输出
样例输入
5
1
8
5
3
2
样例输出
2
#include <iostream>
#include <string>
#include <cstdio>
#include <cmath>
#include <cstring>
#include <algorithm>
#include <vector>
#include <queue>
#include <deque>
#include <map>
#define range(i,a,b) for(int i=a;i<=b;++i)
#define LL long long
#define rerange(i,a,b) for(int i=a;i>=b;--i)
#define fill(arr,tmp) memset(arr,tmp,sizeof(arr))
using namespace std;
pair<int,int>aa[];
int n,ans=;
bool vis[];
bool cmp(pair<int,int>a,pair<int,int>b){
if(a.first!=b.first)return a.first<b.first;
return a.second<b.second;
}
void init(){
cin>>n;
range(i,,n-){
cin>>aa[i].first;
aa[i].second=i;
}
sort(aa,aa+n,cmp);
}
void solve(){
int cnt=;
range(i,,n-){
if(aa[i].second>i)++cnt;
if(vis[i])--cnt;
vis[aa[i].second]=true;
ans=max(ans,cnt);
}
cout<<ans<<endl;
}
int main() {
init();
solve();
return ;
}
Out of Sorts II的更多相关文章
- Leetcode 笔记 113 - Path Sum II
题目链接:Path Sum II | LeetCode OJ Given a binary tree and a sum, find all root-to-leaf paths where each ...
- Leetcode 笔记 117 - Populating Next Right Pointers in Each Node II
题目链接:Populating Next Right Pointers in Each Node II | LeetCode OJ Follow up for problem "Popula ...
- 函数式Android编程(II):Kotlin语言的集合操作
原文标题:Functional Android (II): Collection operations in Kotlin 原文链接:http://antonioleiva.com/collectio ...
- 统计分析中Type I Error与Type II Error的区别
统计分析中Type I Error与Type II Error的区别 在统计分析中,经常提到Type I Error和Type II Error.他们的基本概念是什么?有什么区别? 下面的表格显示 b ...
- hdu1032 Train Problem II (卡特兰数)
题意: 给你一个数n,表示有n辆火车,编号从1到n,入站,问你有多少种出站的可能. (题于文末) 知识点: ps:百度百科的卡特兰数讲的不错,注意看其参考的博客. 卡特兰数(Catalan):前 ...
- [LeetCode] Guess Number Higher or Lower II 猜数字大小之二
We are playing the Guess Game. The game is as follows: I pick a number from 1 to n. You have to gues ...
- [LeetCode] Number of Islands II 岛屿的数量之二
A 2d grid map of m rows and n columns is initially filled with water. We may perform an addLand oper ...
- [LeetCode] Palindrome Permutation II 回文全排列之二
Given a string s, return all the palindromic permutations (without duplicates) of it. Return an empt ...
- [LeetCode] Permutations II 全排列之二
Given a collection of numbers that might contain duplicates, return all possible unique permutations ...
随机推荐
- 【Gradient Boosted Decision Tree】林轩田机器学习技术
GBDT之前实习的时候就听说应用很广,现在终于有机会系统的了解一下. 首先对比上节课讲的Random Forest模型,引出AdaBoost-DTree(D) AdaBoost-DTree可以类比Ad ...
- 【Feasibility of Learning】林轩田机器学习基石
这一节的核心内容在于如何由hoeffding不等式 关联到机器学习的可行性. 这个PAC很形象又准确,描述了“当前的可能性大概是正确的”,即某个概率的上届. hoeffding在机器学习上的关联就是: ...
- FlexGrid布局
FlexGrid布局: Grid布局时网格大小是固定的,如果想网格大小不同的界面可以使用FlexGrid布局.FlexGrid是更加灵活的Grid布局.FlexGrid布局类是wx.FlexGridS ...
- Kickstart配置文件解析
参考:https://www.douban.com/note/270359374/?type=likehttp://blog.51cto.com/molinux/548247http://debugo ...
- Opencv3.3.1安装包
这个资源是Opencv3.3.1安装包,包括Windows软件包,Android软件包,IOS软件包,还有opencv的源代码:需要的下载吧. 点击下载
- css控制文字模糊
*{ color: transparent; text-shadow: #111 0 0 5px; }
- python获取文件夹下数量
import os totalSize = 0 fileNum = 0 dirNum = 0 def visitDir(path): global totalSize global fileNum g ...
- 【bzoj4883】[Lydsy2017年5月月赛]棋盘上的守卫 最小环套树森林
题目描述 在一个n*m的棋盘上要放置若干个守卫.对于n行来说,每行必须恰好放置一个横向守卫:同理对于m列来说,每列必须恰好放置一个纵向守卫.每个位置放置守卫的代价是不一样的,且每个位置最多只能放置一个 ...
- 原来Java大数据才是真正的高富帅!
大数据时代,中国IT环境也将面临重新洗牌,不仅仅是企业,更是程序员们转型可遇而不可求的机遇. 国内大多数大型互联网公司的程序员被称作研发工程师,但实际上国内几乎没有研发项目,只能叫做开发.开发程序员的 ...
- js加解密的算法
//字符串和数字互转 var str="a" var r = str.charCodeAt(0); //97 10进制 console.log(r); var t=String.f ...