LeetCode77:Combinations
Given two integers n and k, return all possible combinations of k numbers out of 1 … n.
For example,
If n = 4 and k = 2, a solution is:
[
[2,4],
[3,4],
[2,3],
[1,2],
[1,3],
[1,4],
]
Hide Tags Backtracking
给定一个数n。求1到n之间的全部的k个数的组合。
这个题目能够在纸上画下草图,明显能够用递归求解。递归的终止条件是k=0,而且因为须要将组合保存到集合vector中,还须要使用回溯法来保存数据。
runtime:8ms
class Solution {
public:
vector<vector<int>> combine(int n, int k) {
vector<vector<int>> result;
vector<int> vec;
helper(1,n,k,vec,result);
return result;
}
void helper(int first,int last,int k,vector<int> & vec,vector<vector<int>> & result)
{
if(k==0)
{
result.push_back(vec);
return ;
}
for(int i=first;i<=last-k+1;i++)
{
vec.push_back(i);
helper(i+1,last,k-1,vec,result);
vec.pop_back();
}
}
};
LeetCode77:Combinations的更多相关文章
- LeetCode77. Combinations(剑指offer38-2)
Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. Example: I ...
- Leetcode77. Combinations组合
给定两个整数 n 和 k,返回 1 ... n 中所有可能的 k 个数的组合. 示例: 输入: n = 4, k = 2 输出: [ [2,4], [3,4], [2,3], [1,2], [1,3] ...
- [Swift]LeetCode77. 组合 | Combinations
Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. Example: I ...
- Combinations
Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For exampl ...
- [LeetCode] Factor Combinations 因子组合
Numbers can be regarded as product of its factors. For example, 8 = 2 x 2 x 2; = 2 x 4. Write a func ...
- [LeetCode] Combinations 组合项
Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For exampl ...
- [LeetCode] Letter Combinations of a Phone Number 电话号码的字母组合
Given a digit string, return all possible letter combinations that the number could represent. A map ...
- Leetcode 254. Factor Combinations
Numbers can be regarded as product of its factors. For example, 8 = 2 x 2 x 2; = 2 x 4. Write a func ...
- 17. Letter Combinations of a Phone Number
题目: Given a digit string, return all possible letter combinations that the number could represent. A ...
随机推荐
- Java--finally
finally 子句(clause)是不是总会执行??? package com.volshell.test; public class Main { public static void main( ...
- POJ 2451 Uyuw's Concert(半平面交nlgn)
//#pragma comment(linker, "/STACK:16777216") //for c++ Compiler #include <stdio.h> # ...
- 笔记之Cyclone IV 第一卷第二章Cyclone IV器件的逻辑单元和逻辑阵
逻辑单元 (LE) 在 Cyclone IV 器件结构中是最小的逻辑单位.LE 紧密且有效的提供了高级功能的逻辑使用.每个 LE 有以下特性 ■ 一个四口输入的查找表 (LUT),以实现四种变量的任何 ...
- jQuery如何设置自增自减值
一直不是很记得jquery中怎么设置自增值,比如当点击按钮时 div在当前宽度基础上增加宽度100px,可以这样写: $('button.test').click(function(){ $('div ...
- QT5.6 编译SQLServer驱动
简要说下编译的主要步骤 @1:打开vs2015的命令行编译环境 ‘ @2:进入到cd到源码目录:cd C:\Qt\Qt5.6.0\5.6\Src\qtbase\src\plugins\sqldrive ...
- NGUI出现Shader wants normals, but the mesh UIAtlas doesn't have them
NGUI出现Shader wants normals, but the mesh UIAtlas doesn't have them,没有网格法线,打开UI Root上 UIPanel组建上的 Nor ...
- cygrunsrv: Error starting a service: QueryServiceStatus: Win32 error 1062: 解决办法
问题原因:很可能是/var/log的权限设置不正确.首先执行 mkpasswd 和 mkgroup 重新生成权限信息,再删除sshd服务,重新配置 解决办法: $ mkpasswd -l > / ...
- javascript每日一练(六)——事件一
一.event对象 var oEvent = ev || event;//获取事件对象 oEvent.clientX oEvent.clientY//获取鼠标坐标 oEvent.cancelBubbl ...
- android之View的启动过程
转自:http://www.cdtarena.com/gpx/201308/9607.html 程序里调用了onSizeChanged方法进行了一些设置,不知道onSizeChanged是在什么时候启 ...
- 高性能IO模型浅析(彩图解释)good
服务器端编程经常需要构造高性能的IO模型,常见的IO模型有四种: (1)同步阻塞IO(Blocking IO):即传统的IO模型. (2)同步非阻塞IO(Non-blocking IO):默认创建的s ...