hdu 1228

Description

读入两个小于100的正整数A和B,计算A+B. 
需要注意的是:A和B的每一位数字由对应的英文单词给出. 

 

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 

 

Output

对每个测试用例输出1行,即A+B的值. 

 

Sample Input

one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

 

Sample Output

3
90
96

 

 

考虑好空格和加数的位数就可以了

#include<bits/stdc++.h>
#define one 1
#define two 2
#define three 3
#define four 4
#define five 5
#define six 6
#define seven 7
#define eight 8
#define nine 9
#define zero 0
using namespace std;
    char a[];
    int i=;
    int t=;
    int num[];
    int con=;
    int flag=;
int main()
{

    while(scanf("%c",&a[i])){
        if(a[i]>='a'&&a[i]<='z')
            {
                con++;
                i++;
            }
            else if(a[i]=='+') {i++;flag =t;}
            else if(a[i]!='=')
            {

                if(con==)
                {
                    if(a[i-]=='o'&&a[i-]=='n') num[t++]=;
                    else if(a[i-]=='t'&&a[i-]=='w') num[t++]=;
                    else if(a[i-]=='s') num[t++]=;
                }
                else if(con==)
                {
                    if(a[i-]=='u') num[t++]=;
                    else if(a[i-]=='v') num[t++]=;
                    else if(a[i-]=='n') num[t++]=;
                    else if(a[i-]=='r') num[t++]=;
                }
                else if(con==)
                {
                    if(a[i-]=='e') num[t++]=;
                    else if(a[i-]=='n') num[t++]=;
                    else if(a[i-]=='t') num[t++]=;
                 }
                con=;
                i++;
            }
            else if(a[i]=='=')
            {
                if(num[]==num[]&&num[]==) return ;
                if(t==) cout<<num[]+num[]<<endl;
                else if(t==&&flag==) cout<<num[]*+num[]+num[]<<endl;
                else if(t==&&flag==) cout<<num[]+num[]*+num[]<<endl;
                else cout<<num[]*+num[]+num[]*+num[]<<endl;
                memset(a,NULL,sizeof(a));
                i=;
                con=;
                memset(num,NULL,sizeof(num));
                t=;
                flag=;
            }

        }
    }