Description

Standard web browsers contain features to move backward and forward among the pages recently visited. One way to implement these features is to use two stacks to keep track of the pages that can be reached by moving backward and forward. In this problem, you are asked to implement this. 
The following commands need to be supported: 
BACK: Push the current page on the top of the forward stack. Pop the page from the top of the backward stack, making it the new current page. If the backward stack is empty, the command is ignored. 
FORWARD: Push the current page on the top of the backward stack. Pop the page from the top of the forward stack, making it the new current page. If the forward stack is empty, the command is ignored. 
VISIT : Push the current page on the top of the backward stack, and make the URL specified the new current page. The forward stack is emptied. 
QUIT: Quit the browser. 
Assume that the browser initially loads the web page at the URL http://www.acm.org/

Input

Input is a sequence of commands. The command keywords BACK, FORWARD, VISIT, and QUIT are all in uppercase. URLs have no whitespace and have at most 70 characters. You may assume that no problem instance requires more than 100 elements in each stack at any time. The end of input is indicated by the QUIT command.

Output

For each command other than QUIT, print the URL of the current page after the command is executed if the command is not ignored. Otherwise, print "Ignored". The output for each command should be printed on its own line. No output is produced for the QUIT command.

Sample Input

VISIT http://acm.ashland.edu/
VISIT http://acm.baylor.edu/acmicpc/
BACK
BACK
BACK
FORWARD
VISIT http://www.ibm.com/
BACK
BACK
FORWARD
FORWARD
FORWARD
QUIT

Sample Output

http://acm.ashland.edu/
http://acm.baylor.edu/acmicpc/
http://acm.ashland.edu/
http://www.acm.org/
Ignored
http://acm.ashland.edu/
http://www.ibm.com/
http://acm.ashland.edu/
http://www.acm.org/
http://acm.ashland.edu/
http://www.ibm.com/
Ignored

POJ 1028题目描述的更多相关文章

  1. POJ 1035题目描述

    Description You, as a member of a development team for a new spell checking program, are to write a ...

  2. poj 动态规划题目列表及总结

    此文转载别人,希望自己能够做完这些题目! 1.POJ动态规划题目列表 容易:1018, 1050, 1083, 1088, 1125, 1143, 1157, 1163, 1178, 1179, 11 ...

  3. POJ 动态规划题目列表

    ]POJ 动态规划题目列表 容易: 1018, 1050, 1083, 1088, 1125, 1143, 1157, 1163, 1178, 1179, 1189, 1208, 1276, 1322 ...

  4. poj 1028

    http://poj.org/problem?id=1028 题意(水):做一个游览器的历史记录. back:后退到上一个页面,当上一个页面没有时,输出ignored. forward:向前一个页面, ...

  5. poj 1028 Web Navigation(模拟)

    题目链接:http://poj.org/problem? id=1028 Description Standard web browsers contain features to move back ...

  6. poj 1028 Web Navigation 【模拟题】

    题目地址:http://poj.org/problem?id=1028 测试样例: Sample Input VISIT http://acm.ashland.edu/ VISIT http://ac ...

  7. {POJ}{动态规划}{题目列表}

    动态规划与贪心相关: {HDU}{4739}{Zhuge Liang's Mines}{压缩DP} 题意:给定20个点坐标,求最多有多少个不相交(点也不相交)的正方形 思路:背包问题,求出所有的正方形 ...

  8. poj 1028 Web Navigation

    Web Navigation Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 31088   Accepted: 13933 ...

  9. POJ动态规划题目列表

    列表一:经典题目题号:容易: 1018, 1050, 1083, 1088, 1125, 1143, 1157, 1163, 1178, 1179, 1189, 1191,1208, 1276, 13 ...

随机推荐

  1. Java主要有那几种文件类型,各自作用

    java提供了两类数据类型:基本类型,引用类型. 1.基本类型包括:boolean ,byte,char,int,short,float,long,double,值得注意的是:在原始数据类型中,除了b ...

  2. 浅谈WPF页间导航

    浅谈WPF页间导航 使用导航的目的是从一个页面进入到另一个页面.无论是预先决定的线性顺序(向导)还是基于层次的用户驱动程序(大部分网站的形式),或者动态生成的路径,主要有3种方法实现:调用Naviga ...

  3. sql 语句大小写的问题

    关键字不区分大小写 例如 select ,from, 大小写均可 标识符区分大小写 例如 表名,列名 标识符如果不加双引号,默认是按大写执行 标识符如果加双引号,则是按原始大小写执行 但是,当表名加上 ...

  4. 10. 求N分之一序列前N项和

    求N分之一序列前N项和 #include <stdio.h> int main() { int i, n; double item, sum; while (scanf("%d& ...

  5. Gmail 启用 POP 标准配置说明:

    接收邮件 (POP3) 服务器 - 要求 SSL:pop.gmail.com使用 SSL:是端口:995 发送邮件 (SMTP) 服务器 - 要求 TLS 或 SSL:smtp.gmail.com使用 ...

  6. Ubuntu kill命令用法详解

    转自:Ubuntu kill命令用法详解 1. kill   作用:根据进程号杀死进程   用法: kill [信号代码] 进程ID   root@fcola:/# ps -ef | grep sen ...

  7. C++ 读写文件流

    1. 读文件流  string readpro(const char* path) {   ifstream infile(path);   char buf[1024];   string mess ...

  8. Java中 static/transient,final/volatile 说明

    你可以任意使用如下的修改限定关键字来定义一个字段:final或者volatile和/或者static和/或者transient. 如果你将一个字段定义为final,编译器将确保字段当成一个常量——只读 ...

  9. 浅谈 举家搬迁静态文件到CDN

    由于七牛CDN最近做活动,对于标准用户可以免费使用如下优惠 10 GB 存储空间 10 G/月 下载流量 10 万次/月 PUT/DELETE 请求 100 万次/月 GET 请求 以上这些指标直接就 ...

  10. sqlserver 通过convert取得指定格式的时间

    http://msdn.microsoft.com/zh-cn/library/ms187928(v=sql.105).aspx CONVERT(NVARCHAR(10),Created,112) 不 ...