基于js的数据结构与算法-数组

---

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

/**
* @param {number[]} nums
* @param {number} target
* @return {number[]}
*/
var twoSum = function(nums, target) {
　　for(var i=0;i<nums.length;i++){
　　　　for(var j=i+1;j<nums.length;j++){
　　　　　　if(nums[i] + nums[j] == target){}

　　　　　　return [i,j];

　　　　　　}
　　　　}
　　　　}
　};