Candy Distribution_找规律
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 6012 | Accepted: 3341 |
Description
N children standing in circle who are numbered 1 through N clockwise are waiting their candies. Their teacher distributes the candies by in the following way:
First the teacher gives child No.1 and No.2 a candy each. Then he walks clockwise along the circle, skipping one child (child No.3) and giving the next one (child No.4) a candy. And then he goes on his walk, skipping two children (child No.5 and No.6) and giving the next one (child No.7) a candy. And so on.
Now you have to tell the teacher whether all the children will get at least one candy?
Input
The input consists of several data sets, each containing a positive integer N (2 ≤ N ≤ 1,000,000,000).
Output
For each data set the output should be either "YES" or "NO".
Sample Input
2
3
4
Sample Output
YES
NO
YES
【思路】找规律,是2的指数输出yes否则no
#include<iostream>
#include<stdio.h>
#include<string.h>
using namespace std;
int main()
{
long long n;
while(~scanf("%lld",&n))
{
while(n)
{
if(n&) break;//二进制数最右位为1时,若n为1,则为2的指数,否则不能除2了也要退出
n>>=;//相当于每次除2 }
if(n==) printf("YES\n");
else printf("NO\n");
}
return ;
}
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