ZOJ - 3866 Cylinder Candy 【数学】

题目链接

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3866

思路

积分

参考博客

https://blog.csdn.net/u012377575/article/details/45285895

AC代码

#include <cstdio>
#include <cstring>
#include <ctype.h>
#include <cstdlib>
#include <cmath>
#include <climits>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <map>
#include <stack>
#include <set>
#include <numeric>
#include <sstream>
#include <iomanip>
#include <limits>

#define CLR(a) memset(a, 0, sizeof(a))
#define pb push_back

using namespace std;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
typedef pair<string, int> psi;
typedef pair<string, string> pss;

const double PI = acos(-1);
const double E = exp(1);
const double eps = 1e-30;

const int INF = 0x3f3f3f3f;
const int maxn = 5e4 + 5;
const int MOD = 1e9 + 7;

int main()
{
    int T;
    cin >> T;
    while (T--)
    {
        int r, h, d;
        scanf("%d%d%d", &r, &h, &d);
        double v = (r + d) * (r + d) * PI * h + 2 * (2.0 / 3 * d * d * d * PI + r * d * d * PI * PI * 1.0 / 2 + r * r * d * PI);
        double s = 2 * (r + d) * PI * h + 2 * PI * r * r + 2 * (PI * PI * r * d + 2 * PI * d * d);
        printf("%.12lf %.12lf\n", v, s);
    }
}