Flowers

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3679    Accepted Submission(s): 2412

Problem Description
As you know, Gardon trid hard for his love-letter, and now he's spending too much time on choosing flowers for Angel. When Gardon entered the flower shop, he was frightened and dazed by thousands kinds of flowers. "How can I choose!" Gardon shouted out. Finally, Gardon-- a no-EQ man decided to buy flowers as many as possible. Can you compute how many flowers Gardon can buy at most?
 
Input
Input have serveral test cases. Each case has two lines. The first line contains two integers: N and M. M means how much money Gardon have. N integers following, means the prices of differnt flowers.
 
Output
For each case, print how many flowers Gardon can buy at most. You may firmly assume the number of each kind of flower is enough.
 
Sample Input
2 5
2 3
 
Sample Output
2
 #include <iostream>
using namespace std; int main(){
int n, m, num;
while(cin >> n >> m){
int min = ;
for(int i = ; i < n; i++){
cin >> num;
if(num < min)
min = num;
}
cout << m / min << endl;
}
return ;
}

hdu 1587 Flowers的更多相关文章

  1. HDOJ(HDU) 1587 Flowers(水、、)

    Problem Description As you know, Gardon trid hard for his love-letter, and now he's spending too muc ...

  2. HDU 1587 Flowers【贪心】

    题意:给出n种花的价钱,和总的金额m,问最多能够买到多少朵花.先排序,然后就是便宜的花在能够买的范围内能够多买就多买 #include<iostream> #include<cstd ...

  3. hdu 4325 Flowers(区间离散化)

    http://acm.hdu.edu.cn/showproblem.php?pid=4325 Flowers Time Limit: 4000/2000 MS (Java/Others)    Mem ...

  4. HDU 4325 Flowers 树状数组+离散化

    Flowers Problem Description As is known to all, the blooming time and duration varies between differ ...

  5. hdu 1587

    Problem Description As you know, Gardon trid hard for his love-letter, and now he's spending too muc ...

  6. HDU 4325 Flowers(树状数组)

    Flowers Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Sub ...

  7. HDU 4325 Flowers(树状数组+离散化)

    http://acm.hdu.edu.cn/showproblem.php?pid=4325 题意:给出n个区间和m个询问,每个询问为一个x,问有多少个区间包含了x. 思路: 因为数据量比较多,所以需 ...

  8. 2013 多校联合2 D Vases and Flowers (hdu 4614)

    Vases and Flowers Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others ...

  9. (线段树 区间运算求点)Flowers -- hdu -- 4325

    http://acm.hdu.edu.cn/showproblem.php?pid=4325 Flowers Time Limit: 4000/2000 MS (Java/Others)    Mem ...

随机推荐

  1. c#调用c++动态库的一些理解

    调用c++动态库一般我们这样写   [DllImport("UCamer.dll", CallingConvention = CallingConvention.Winapi)] ...

  2. Servlet能读到JSessionID,读不到其它cookie问题

    Servlet的Cookie值保存与获取 今天测试设置和获取Cookie遇到了一点小问题,很奇怪的问题: 把J2ee服务部署在本地 8080端口:访问任何一个服务时,如果客户端没有cookie,则下发 ...

  3. Java Socket 异常 Connection reset

    最近使用Java做Socket客户端,与C的Socket服务端交互.遇到问题:现象是可以从服务端接受小数据,但是如果接受大数据,总是遇到Connection reset的异常:如果把服务端和客户端放到 ...

  4. [Irving]SqlServer 拆分函数用法

    drop function dbo.split  删除自定义函数 dbo.split  函数名 函数 dbo.splitcreate function dbo.split(@c varchar(100 ...

  5. phpMyAdmin安装设置

    phpMyAdmin是一种MySQL的管理工具,它直接从web上去管理MySQL.   假设你的web(网页存放)根目录是 /var/www/ 假设你的主机web访问是这样的 http://192.1 ...

  6. 【Java基础】增强for循环要注意陷阱

    什么是增强for循环 增强for循环是一种简单模式的for循环,为了方便数组和集合的遍历而存在. int[] arr = new int[]{1, 2, 3, 4, 5, 6}; for (int a ...

  7. HW2.18

    public class Solution { public static void main(String[] args) { System.out.println("a" + ...

  8. HW1.7

    public class Solution { public static void main(String[] args) { System.out.println("π = " ...

  9. POJ2689 - Prime Distance(素数筛选)

    题目大意 给定两个数L和U,要求你求出在区间[L, U] 内所有素数中,相邻两个素数差值最小的两个素数C1和C2以及相邻两个素数差值最大的两个素数D1和D2,并且L-U<1,000,000 题解 ...

  10. 问题.NET访问 IIS 元数据库失败。

    问题现象:访问 IIS 元数据库失败. 说明:执行当前 Web 请求期间,出现未处理的异常.请检查堆栈跟踪信息,以了解有关该错误以及代码中导致错误的出处的详细信息. 异常详细信息: System.We ...