从数据库中获取图片编号，然后通过request获取图片下载

import pandas as pd

from pandas.core.dtypes.dtypes import register_extension_dtype

from sqlalchemy import create_engine, engine

初始化数据库连接，使用pymysql模块

Mysql的用户root，密码：mysql，端口33306，数据库xxx

engine = create_engine('mysql+pymysql://root:mysql@localhost:3306/xxx')

查询语句，选出表中的所有数据

print(df.head)

for i in range(29):

sql = '''SELECT * FROM tpcode where IMAGETYPE like '''+str(i+1)+'''.%%' limit 2500; '''

df = pd.read_sql_query(sql, engine)

print(sql)

with open('a.csv', 'w', encoding='utf-8') as file:

pd.DataFrame(columns=['REGNO','IMAGETYPE']).to_csv(file, index=False) # 去除index

for i in range(29):

sql = "SELECT REGNO,IMAGETYPE FROM tpcode where IMAGETYPE like '"+str(i+1)+'.'+"%%"+"' limit 2500; "

print(sql)

df = pd.read_sql_query(sql, engine)

df['IMAGETYPE'] = i+1

df.to_csv(file, mode='a+', index=False,header=False) #追加，不写索引和表头

print(i)

from datetime import datetime

import hashlib

from urllib.parse import unquote, quote

import requests

df = pd.read_csv('a.csv')

a = 0

for i in df['REGNO']:

a = a +1

imgurl = sign_md5s('BrandInfoFind/GetBrandInfoImg', {"RegId": i})

try:

filename = 'image/' +str(i) + '.jpg'

pic = requests.get(imgurl)

if pic.status_code == 200:

with open(filename, 'wb') as fp:

fp.write(pic.content)

fp.close()

if a % 2500 == 0:

print("成功输出类别：",int(a/2500)+1)

except:

print('获取图片失败',i)

[5356570、221790、688751、8168627、4505830、8009223]