Get Your Wish

Get Your Wish

(https://www.luogu.com.cn/problem/P7262)

一个模拟题

解读一下题目：简单来说就是在现在重力的方向上，如果有水滴和电子元件就GG，否则就OK

这里要注意一点，（卡死我这一点，水滴可能不止一滴。

方法：简单判断是否水滴和电子元件处于重力的方向上就好

Acode

 int n,m; cin >> n >> m;
    char begin; cin >> begin;
    vector<pair<int,int>> pa,oo;
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= m; j++) {
            char ch; cin >> ch;
            if(ch == 'o'){
                oo.push_back({i,j});
            }
            if(ch == 'x')pa.push_back({i,j});
        }
    }
    if(!oo.size() || !pa.size())cout << "OK" << endl;
    else{
        for (int i = 0; i < oo.size(); i++) {
            int x = oo[i].first,y = oo[i].second;
            for (int j = 0; j < pa.size(); j++) {
                if(begin == 'v'){
                    if(pa[j].second == y){
                        if(x < pa[j].first){
                            cout << "GG" << endl;
                            exit(0);
                        }
                    }
                }else if(begin == '^'){
                    if(pa[j].second == y){
                        if(x > pa[j].first){
                            cout << "GG" << endl;
                            exit(0);
                        }
                    }
                }else if(begin == '>'){
                    if(pa[j].first == x){
                        if(y < pa[j].second){
                            cout << "GG" << endl;
                            exit(0);
                        }
                    }
                }else if(begin == '<'){
                    if(pa[j].first == x){
                        if(y > pa[j].second){
                            cout << "GG" << endl;
                            exit(0);
                        }
                    }
                }
            }
        }
        cout << "OK" << endl;
    }