python文件夹中文件读取踩坑

Q:

进行数据集图片预处理时，初始命名如下图（Fig1左），发现读取文件时，读取的结构并非如所设想的那样顺序读取

Fig 1

A：

pyhton读取文件的时候，按照文件名的ascii码中的顺序进行逐位排序，于是编写以下代码，更改命名规则，程序如下

 # -*- coding:utf-8 -*-
 # ------------------------------
 # @Time     :2019/5/26 10:55
 # @Author   :jonie
 # @Email    :xxxxx@xx.com
 # @File     :重命名.py
 # Description:实现形如"类名_000x.jpg"的命名方式
 # ------------------------------
 import os
 def re_name(path_name):
     num = 0
     for dir_image in os.listdir(path_name):  # os.listdir() 方法用于返回指定的文件夹包含的文件或文件夹的名字的列表
     # print(dir_image)
         full_path = os.path.abspath(os.path.join(path_name, dir_image))
         # print(full_path)

         if os.path.isdir(full_path):  # 如果是文件夹，继续递归调用
             if not os.path.exists(os.path.join(r"D:\Jonie_Project_scc15\dataset\scene_categories",dir_image)):
                 os.makedirs(os.path.join(r"D:\Jonie_Project_scc15\dataset\scene_categories",dir_image))
             # print(os.path.join(r"D:\Jonie_Project_ot8\data1\scene_categories",dir_image))
             print("isdir")
             re_name(full_path)
             # print(full_path)
         else:  # 如果是文件了
             # pass
             # print(dir_image)
             # print(full_path)
             if dir_image.endswith('.jpg'):
                 cla=full_path.split('\\')[-2]
                 image_name = '%s_%04d.jpg' % (cla, num)  # 注意这里图片名一定要加上扩展名，否则后面imwrite的时候会报错
                 image_name =os.path.join("D:\Jonie_Project_scc15","dataset\scene_categories",cla,image_name)
                 oldname=os.path.join("D:\Jonie_Project_scc15","dataset\scene_categories",cla,image_name)
                 # print(image_name)
                 print(full_path)
                 os.rename(full_path, image_name)
                 num = num + 1
 if __name__ == '__main__':
     re_name(r"D:\Jonie_Project_scc15\dataset\scene_categories")

rename.py

再次进行读取，发现达到预期结果

Fig 2