day12作业答案

2.1
# lst=['asdgg','as','drtysr']
# lst2=[i.upper()  for i in lst if len(i) >3 ]
# print(lst2)
# 2.2
# tu=[(x,y) for x in range(6) if x%2==0 for y in range(6) if y%2==0]
# print(tu)
#
# 2.3
# M=[[1,2,3],[4,5,6],[7,8,9]]
# a=[i[2] for i in M]
# print(a)
#
# 2.4
# a=[i**2 for i in range(50 ) if i %3==0]
# print(a)
#
# 2.5
# a=['python%s期' % i for i in range(1,11)]
# print(a)
#
# 2.6
# a=[(i,i+1) for i in range(6)]
# print(a)
#
# 2.7
# a=[i for i in range(0,20,2)]
# print(a)
#
# 2.8
# l1=['alex','wusir','老男孩','太白']
# a=[(l1[i]+str(i)) for i in range(4)]
# print(a)
#
# 2.9
# x={
#     'name':'alex',
#     'values':[{'timestamp':1517991992.94,'values':100},
#               {'timestamp':1517992000.94,'values':300},
#               {'timestamp':1517992014.94,'values':300},
#               {'timestamp': 1517992744.94, 'values': 350},
#               {'timestamp': 1517992800.94, 'values': 280},
#
#               ]}
# a=[[i['timestamp'],i['values']] for i in x['values']]
# print(a)