import java.util.Scanner;
public class J714
{
/**
* @taking input from user
*/
public static void main(String[] args)
{
/**
* @taking input from user
*/
Scanner input = new Scanner(System.in);
System.out.print("Enter the length of a square matrix: ");
int n = input.nextInt();
/**
* @declaring the array of n*n size
*/
int[][] board = new int[n][n]; boolean isSameOnARow = false; boolean isSameOnAColumn = false;
boolean isSameOnADiagonal = false; boolean isSameOnASubdiagonal = false;
/**
* @performing the fucntions
*/
for (int i = 0; i < board.length; i++) {
for (int j = 0; j < board[0].length; j++) {
board[i][j] = (int)(Math.random() * 2.0D);
System.out.print(board[i][j]);
}
System.out.println();
}
/**
* @taking a for loop
*/
for (int i = 0; i < board.length; i++) {
boolean same = true;
for (int j = 1; j < board[0].length; j++) {
/**
* @checking the conditions
*/
if (board[i][0] != board[i][j]) {
same = false;
break;
}
}
/**
* @checking the conditions
*/
if (same) {
System.out.println("All " + board[i][0] + "'s on row " + i);
isSameOnARow = true;
}
}
for (int j = 0; j < board[0].length; j++) {
boolean same = true;
for (int i = 1; i < board.length; i++) {
if (board[0][j] != board[i][j]) {
same = false;
break;
}
}
if (same) {
System.out.println("All " + board[0][j] + "'s on column " + j);
isSameOnAColumn = true;
}
}
boolean same = true;
for (int i = 1; i < board.length; i++) {
if (board[0][0] != board[i][i]) {
same = false;
break;
}
}
if (same) {
System.out.println("All " + board[0][0] + "'s on major diagonal");
isSameOnADiagonal = true;
}/**
* @checking the conditions
*/
same = true;
for (int i = 1; i < board.length; i++) {
if (board[0][(board.length - 1)] != board[i][(board.length - 1 - i)]) {
same = false;
break;
}
}
/**
* @checking the conditions and printing the required elements
*/
if (same) {
System.out.println("All " + board[0][(board.length - 1)] + "'s on sub-diagonal");
isSameOnASubdiagonal = true;
}
if (!isSameOnARow) {
System.out.println("No same numbers on a row");
}
if (!isSameOnAColumn) {
System.out.println("No same numbers on a column");
}
if (!isSameOnADiagonal) {
System.out.println("No same numbers on the major diagonal");
}
if (!isSameOnASubdiagonal)
System.out.println("No same numbers on the sub-diagonal");
}
}
import java.util.Scanner;
public class ExploringMatrix
{
public static void main (String[] args)
{
Scanner scan = new Scanner(System.in);
System.out.print("Enter the size for the matrix: ");
int size = scan.nextInt();
int[][] m = new int[size][size]; for (int i =0;i<size;i++)
{
for (int j =0;j<size;j++)
{
m[i][j] = (int) (Math.random()*2);
System.out.print(m[i][j]);
}
System.out.println();
}
boolean letitbe;
//Row
int j =0; boolean row=false, column=false, major =false, sub = false;
for(int i=0; i<size;i++)
{
letitbe = true;
for (j =0;j<size-1;j++)
{
if (m[i][j] != m[i][j+1]) letitbe = false;
}
if (letitbe)
{
System.out.println("All " + m[i][j] + "s on row " + i);
row = true;
}
}
//Column
for(int i=0; i<size;i++)
{
letitbe = true;
for (j =0;j<size-1;j++)
{
if (m[j][i] != m[j+1][i]) letitbe = false;
}
if (letitbe)
{
System.out.println("All " + m[j][i] + "s on column " + i);
column = true;
} }
//Major diagonal, there is only one eh?
letitbe = true;
for (int i=0;i<size-1;i++)
{
if (m[i][i]!= m[i+1][i+1]) letitbe = false;
}
if (letitbe)
{
System.out.println("All " + m[0][0] + "s on major diagonal");
major = true;
} letitbe = true;
for (int i=0;i<size-1;i++)
{
if (m[i][size-i-1]!= m[i+1][size-i-1-1]) letitbe = false;
}
if (letitbe)
{
System.out.println("All " + m[0][size-1] + "s on sub-diagonal");
sub = true;
} if ( column == false) System.out.println("No same numbers on a column");
if ( row == false) System.out.println("No same numbers on a row");
if ( major == false) System.out.println("No same numbers on the major diagonal");
if ( sub == false) System.out.println("No same numbers on the sub-diagonal");
}
}
Exploring Matricies in Java
Problem:
Write a program that prompts the user to enter the length of a square matrix, randomly fills in 0s and 1s into the matrix,
prints the matrix, and finds the rows, columns, and diagonals with all 0s or 1s. Output:
Enter the size for the matrix: 4
1000
0111
0101
0100
No same numbers on a column
No same numbers on a row
No same numbers on the major diagonal
No same numbers on the sub-diagonal

Exploring Matrix的更多相关文章

  1. [转]第四章 使用OpenCV探测来至运动的结构——Chapter 4:Exploring Structure from Motion Using OpenCV

    仅供参考,还未运行程序,理解部分有误,请参考英文原版. 绿色部分非文章内容,是个人理解. 转载请注明:http://blog.csdn.net/raby_gyl/article/details/174 ...

  2. Searching a 2D Sorted Matrix Part I

    Write an efficient algorithm that searches for a value in an n x m table (two-dimensional array). Th ...

  3. A geometric interpretation of the covariance matrix

    A geometric interpretation of the covariance matrix Contents [hide] 1 Introduction 2 Eigendecomposit ...

  4. [NLP] cs224n-2019 Assignment 1 Exploring Word Vectors

      CS224N Assignment 1: Exploring Word Vectors (25 Points)¶ Welcome to CS224n! Before you start, make ...

  5. angular2系列教程(十一)路由嵌套、路由生命周期、matrix URL notation

    今天我们要讲的是ng2的路由的第二部分,包括路由嵌套.路由生命周期等知识点. 例子 例子仍然是上节课的例子:

  6. Pramp mock interview (4th practice): Matrix Spiral Print

    March 16, 2016 Problem statement:Given a 2D array (matrix) named M, print all items of M in a spiral ...

  7. Atitit Data Matrix dm码的原理与特点

    Atitit Data Matrix dm码的原理与特点 Datamatrix原名Datacode,由美国国际资料公司(International Data Matrix, 简称ID Matrix)于 ...

  8. Android笔记——Matrix

    转自:http://www.cnblogs.com/qiengo/archive/2012/06/30/2570874.html#translate Matrix的数学原理 在Android中,如果你 ...

  9. 通过Matrix进行二维图形仿射变换

    Affine Transformation是一种二维坐标到二维坐标之间的线性变换,保持二维图形的"平直性"和"平行性".仿射变换可以通过一系列的原子变换的复合来 ...

随机推荐

  1. Linux argc,argv详解

    来源:微信公众号「编程学习基地」 @ 目录 argc,argv是什么 如何解析程序参数 "选项"是什么? "选项字符串"是什么 解析参数 argc,argv是什 ...

  2. Convolutional Neural Network-week2编程题2(Residual Networks)

    1. Residual Networks(残差网络) 残差网络 就是为了解决深网络的难以训练的问题的. In this assignment, you will: Implement the basi ...

  3. 提升使用Linux效率的小操作

    提升使用Linux效率的小操作 保存更新? 本文记录了个人在使用Linux时觉得好用的一些快捷方式/功能: 为那种知道了能提高效率,但是的不知道也并没有影响的操作. 历史命令 该操作用于快速查看已使用 ...

  4. (一)、Docker 简介

    1.Docker镜像是什么? 镜像是一种轻量级.可执行的独立软件包,用来打包软件运行环境和基于运行环境开发的软件,它包含运行某个软件所需的所有内容,包括代码.运行时.库.环境变量和配置文件. 2.Do ...

  5. 2021.10.27考试总结[冲刺NOIP模拟17]

    T1 宝藏 发现每个数成为中位数的长度是关于权值单调的.线段树二分判断是否合法,单调指针扫即可. 考场上写了二分,平添\(\log\). \(code:\) T1 #include<bits/s ...

  6. boost编译中的细节问题

    原文链接 http://www.cppblog.com/Robertxiao/archive/2013/01/06/197022.html 生成文件命名规则:boost中有许多库,有的库需要编译.而有 ...

  7. 8M的摄像头,30fps摄像时,60hz的LCD刷新频率,请问camera每秒向BB传输多少数据,如何计算

    8M的摄像头,30fps摄像时,60hz的LCD刷新频率,请问camera每秒向BB传输多少数据,如何计算 xiang2012 Post at 2012/8/7 10:37:33 8M的摄像头,30f ...

  8. Python触发异常

    我们可以使用raise语句自己触发异常,raise语法格式如下: raise [Exception [, args [, traceback]]] 语句中 Exception 是异常的类型(例如,Na ...

  9. Flink 实践教程:入门(1):零基础用户实现简单 Flink 任务

    作者:腾讯云流计算 Oceanus 团队 流计算 Oceanus 简介 流计算 Oceanus 是大数据产品生态体系的实时化分析利器,是基于 Apache Flink 构建的具备一站开发.无缝连接.亚 ...

  10. longest-consecutive-sequence leetcode C++

    Given an unsorted array of integers, find the length of the longest consecutive elements sequence. F ...