F - Candy Bags
A. Candy Bagstime limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
Gerald has n younger brothers and their number happens to be even. One day he bought n2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer k from 1 to n2 he has exactly one bag with kcandies.
Help him give n bags of candies to each brother so that all brothers got the same number of candies.
InputThe single line contains a single integer n (n is even, 2 ≤ n ≤ 100) — the number of Gerald's brothers.
OutputLet's assume that Gerald indexes his brothers with numbers from 1 to n. You need to print n lines, on the i-th line print n integers — the numbers of candies in the bags for the i-th brother. Naturally, all these numbers should be distinct and be within limits from 1 to n2. You can print the numbers in the lines in any order.
It is guaranteed that the solution exists at the given limits.
Examplesinput2output1 4
2 3NoteThe sample shows Gerald's actions if he has two brothers. In this case, his bags contain 1, 2, 3 and 4 candies. He can give the bags with 1 and 4 candies to one brother and the bags with 2 and 3 to the other brother.
这个太水了 从两边按要求输出就好
附AC代码:
#include<bits/stdc++.h>
using namespace std; int main(){
int n;
cin>>n;
int l=,r=n*n;
for(int i=;i<n;i++){
int temp=n;
while(temp--){
cout<<l++<<" "<<r--<<" ";
temp--;
}
cout<<endl;
}
return ;
}
F - Candy Bags的更多相关文章
- Candy Bags
读懂了题就会发现这是个超级大水题 Description Gerald has n younger brothers and their number happens to be even. One ...
- A. Candy Bags
A. Candy Bags http://codeforces.com/problemset/problem/334/A time limit per test 1 second memory l ...
- 334A Candy Bags
A. Candy Bags time limit per test 1 second memory limit per test 256 megabytes input standard input ...
- @atcoder - Japanese Student Championship 2019 Qualification - F@ Candy Retribution
目录 @description@ @solution@ @accepted code@ @details@ @description@ 请找到满足以下条件的长度为 N 的非负整数序列 A1, A2, ...
- codeforces A. Candy Bags 解题报告
题目链接:http://codeforces.com/contest/334/problem/A 题意:有n个人,将1-n袋(第 i 袋共有 i 颗糖果,1<= i <=n)所有的糖 ...
- codeforces 334A - Candy Bags
忘了是偶数了,在纸上画奇数画了半天... #include<cstdio> #include<cstring> #include<cstdlib> #include ...
- Candy Distribution
Kids like candies, so much that they start beating each other if the candies are not fairly distribu ...
- Codeforces Round #194 (Div.1 + Div. 2)
A. Candy Bags 总糖果数\(\frac{n^2(n^2+1)}{2}\),所以每人的数量为\(\frac{n}{2}(n^2+1)\) \(n\)是偶数. B. Eight Point S ...
- CodeForces Round 194 Div2
A. Candy Bagstime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputs ...
随机推荐
- Java 读写文件大全
原文:http://www.open-open.com/code/view/1423281836529 java中多种方式读文件 一.多种方式读文件内容. 1.按字节读取文件内容 2.按字符读取文件内 ...
- 【CV知识学习】神经网络梯度与归一化问题总结+highway network、ResNet的思考
这是一篇水货写的笔记,希望路过的大牛可以指出其中的错误,带蒟蒻飞啊~ 一. 梯度消失/梯度爆炸的问题 首先来说说梯度消失问题产生的原因吧,虽然是已经被各大牛说烂的东西.不如先看一个简单的网络结构 ...
- 79.iOS 设备的UI规范和iOS各控件默认高度
iOS设备的UI 规范 iPhone界面尺寸 iPhone图标尺寸 iPad的设计尺寸 iPad图标尺寸 iPhone设备尺寸分辨率比例 iPhone各设备 launch image iOS 各种控件 ...
- [Servlet&JSP] 标准标签
在JSP的规范中提供了一些标准标签(Standard Tag),全部的容器都支持这些标签,它能够协助编写JSP时降低Scriptlet的使用. 全部的标准标签都使用jsp:作为前置.这些标准标签是在J ...
- 安卓自己定义View进阶-Canvas之绘制基本形状
Canvas之绘制基本形状 作者微博: @GcsSloop [本系列相关文章] 在上一篇自己定义View分类与流程中我们了解自己定义View相关的基本知识,只是,这些东西依然还是理论,并不能拿来(zh ...
- IOS UIPickView+sqlite 选择中国全部城市案例
1.案例简单介绍 通过读取文件.将中国全部城市写入sqlite数据库中,现通过UIPickView实现中国全部城市的选择,效果图例如以下所看到的 2.城市对象模型 中国全部城市数据请看http://b ...
- react 创建组件 (二)component
因为ES6对类和继承有语法级别的支持,所以用ES6创建组件的方式更加优雅,下面是示例: import React from 'react'; class Greeting extends React. ...
- 关于文件与文件系统的压缩与打包命令-Linux(笔记)
1.gzip : 压缩命令 gzip [-cdtv#] 文件名称 (后缀为.gz) -c :将压缩的数据输出到屏幕上,可通过数据流重定向处理 -d : 解压缩的參数 -v : 能够显示源文件/压缩文件 ...
- C# partial分部类和分部方法
1.https://www.cnblogs.com/xcsn/p/7533238.html 它是一个关键字修饰符.可以将类或结构.接口或方法的定义拆分到两个或更多个源文件中. 每个源文件包含类型或方法 ...
- Hive JOIN的基本操作 及 内部实现
1.HIVE基本操作: [一起学Hive]之十一-Hive中Join的类型和用法 注:HIve不支持非等值连接: 什么是等值连接: //Oracle SQL 不等值连接 //通过不等值连接查找7788 ...