Given an integer n, generate a square matrix filled with elements from 1 to n2 in
spiral order.

For example,

Given n = 3,

You should return the following matrix:

[
[ 1, 2, 3 ],
[ 8, 9, 4 ],
[ 7, 6, 5 ]
]

思路:与上一篇类似。仅仅要不越界就ok

public class Solution {
public int[][] generateMatrix(int n) {
if (n == 0)
return new int[0][0]; int[][] matrix = new int[n][n];
int x1 = 0;
int y1 = 0;
int x2 = matrix.length - 1;
int y2 = matrix[0].length - 1;
int i = 0, j = 1;
while (x1 <= x2 && y1 <= y2) {
// up row
for (i = y1; i <= y2; ++i, j++)
matrix[x1][i] = j;
// right column
for (i = x1 + 1; i <= x2; ++i, j++)
matrix[i][y2] = j;
// bottom row
for (i = y2 - 1; x2 != x1 && i >= y1; --i, j++)
matrix[x2][i] = j;
// left column
for (i = x2 - 1; y1 != y2 && i > x1; --i, j++)
matrix[i][y1] = j; x1++;
y1++;
x2--;
y2--;
}
return matrix;
}
}

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