【PAT】1041. Be Unique (20)

题目链接：http://pat.zju.edu.cn/contests/pat-a-practise/1041

题目描述：

Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1, 10⁴]. The first one who bets on a unique number wins. For example, if there are 7 people betting on 5 31 5 88 67 88 17, then the second one who bets on 31 wins.

Input Specification:

Each input file contains one test case. Each case contains a line which begins with a positive integer N (<=10⁵) and then followed by N bets. The numbers are separated by a space.

Output Specification:

For each test case, print the winning number in a line. If there is no winner, print "None" instead.

Sample Input 1:

7 5 31 5 88 67 88 17

Sample Output 1:

31

Sample Input 2:

5 888 666 666 888 888

Sample Output 2:

None

分析：（1）直接用查询表。（2）有个坑爹的陷阱，用cin输入会超时，但是用scanf输入去可以通过。原因是？？？

参考代码：

#include<iostream>
#include<cstdio>
#include<string.h>
using namespace std;
int result[10000 + 5];
int input[100000 + 5];
int main()
{
	int n;
	cin>>n;
	int i;
	int temp;
	bool flag = false;

	for(i=0; i<n; i++)
	{
		//cin>>input[i];   用cin会超时, 用scanf不会
		scanf("%d",&input[i]);
		result[ input[i] ]++;
	}

	for(i=0; i<n; i++)
	{
		if(result[ input[i] ] == 1)
		{
			flag = true;
			break;
		}
	}
	if(flag)
		cout<<input[i]<<endl;

	else
		cout<<"None"<<endl;
	return 0;
}