Gym 100507D Zhenya moves from the dormitory (模拟)
Zhenya moves from the dormitory
题目链接:
http://acm.hust.edu.cn/vjudge/contest/126546#problem/D
Description
After moving from his parents’ place Zhenya has been living in the University dormitory for a month.
However, he got pretty tired of the curfew time and queues to the shower room so he took a fancy for
renting an apartment. It turned out not the easiest thing in the world to make a choice. One can live in
a one bedroom apartment or in a two bedroom apartment, alone or share it with a friend. Zhenya can
afford to rent an apartment of any type alone, but he can share only a two bedroom apartment. If two
people share an apartment, each pays half of the rent. Every apartment has its own advantages like part
of the town, floor, view from the windows, etc., which Zhenya is going to take into account to make a
decision.
Besides that, his friends, he’s ready to share an apartment with, also have certain advantages. For example,
Igor is a good cook, Dima is tidy, Kostya is a good cook and at the same time can explain how to solve
functional analysis problems. And do not forget that living alone has its own bright sides.
Zhenya has already prepared the list of suitable apartments and possible housemates. Zhenya has estimated
in units the advantages of each apartment and each friend and also the advantages of living alone. Besides,
he knows the maximum sum of money he and each of his friends is ready to pay for the apartment. Help
Zhenya to make a decision.
Input
2015. Zhenya moves from the dormitory Time limit: 1.0 secondMemory limit: 64 MB After moving from hi ... Zhenya moves from parents 题目链接: http://acm.hust.edu.cn/vjudge/contest/126546#problem/C Description Z ... After moving from his parents’ place Zhenya has been living in the University dormitory for a month. ... 线段树每个结点维护两个值,分别是这个区间的 负债 和 余钱. 按时间顺序从前往后看的时候,显然负债是单调不减的. 按时间顺序从后往前看的时候,显然余钱也是单调不减的,因为之前如果有余钱,可能会增加现在 ... Zhenya moves from parents Time limit: 1.0 secondMemory limit: 64 MB Zhenya moved from his parents’ h ... 2014. Zhenya moves from parents Time limit: 1.0 secondMemory limit: 64 MB Zhenya moved from his pare ... Zhenya moved from his parents' home to study in other city. He didn't take any cash with him, he onl ... 题意:儿子身无分文出去玩,只带了一张他爸的信用卡,当他自己现金不足的时候就会用信用卡支付,然后儿子还会挣钱,挣到的钱都是现金,也就是说他如果有现金就会先花现金,但是有了现金他不会还信用卡的钱.他每花一 ... 题意:给定 n 个裁判,然后每个都一些题目,现在要从每一个按顺序去选出 k 个题,并且这 k 个要按不递减顺序,如果没有,就用50补充. 析:就按他说的来,直接模拟就好. 代码如下: #pragma ... 术语和概念 屏幕尺寸 屏幕的物理尺寸,以屏幕的对角线长度作为依据(比如 2.8寸, 3.5寸). 简而言之, Android把所有的屏幕尺寸简化为三大类:大,正常,和小. 程序可以针对这三种尺 ... BUG:昨天在使用activity之间传值的时候,遇到了一个bug,该bug为:Activity A启动Activity B,然后在Activity B中取到一个值,并通过back键返回到Activi ... SAM好题,显然我们不能与每个后缀都去算LCP 考虑对询问串每一位算贡献,先构建出逆序构建自动机,这样我们得到了原串的后缀树(parent树) 根据parent树的定义,一个节点对应字符串出现的位置对 ... 因为题目要求同列相邻两格不同色,所以列与列之间不影响,可以逐列染色. 如果一个格子的上面相邻的格子,已经被染色则染这个格子的时候,共有k-1中选择. 反过来,如果一个格子位于第一列,或者上面相邻的格子 ... 将最短路图找出来,跑maxflow即可.有注意到数据范围.然后输出的时候%dWA了三次QAQ... #include<cstdio> #include<cstring> #in ... configration这个类是分析hadoop源代码一个很好地入口. 先从需求说起.对于一个大型的文件系统,基于配置文件可以增强灵活性.congfigration类就是为了管理配置文件的. 配置文件 ... [反汇编练习] 160个CrackMe之018. 本系列文章的目的是从一个没有任何经验的新手的角度(其实就是我自己),一步步尝试将160个CrackMe全部破解,如果可以,通过任何方式写出一个类似于注 ... 题意:给定一个序列,第i个元素代表第i天这支股票的价格,问在最佳时机买入和卖出能赚多少钱?只买一次,且仅1股,假设本钱无限. 思路:要找一个最低价的时候买入,在最高价的时候卖出利润会最大.但是时间是不 ... 网络抽象层单元类型 (NALU): NALU头由一个字节组成,它的语法如下: +---------------+ |0|1|2|3|4|5|6|7| +-+-+-+-+-+-+-+ ... 写作缘由: 平时再用js写函数的时候,一般都是以惯例 function fn () {} 的方式来声明一个函数,在阅读一些优秀插件的时候又不免见到 var fn = function () {} 这种 ...
The first line contains three integers: the maximum sum Zhenya is ready to pay monthly, the advantages of
living alone in a one bedroom apartment and the advantages of living alone in a two bedroom apartment.
The second line contains an integer
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