Gym 100507D Zhenya moves from the dormitory (模拟)
Zhenya moves from the dormitory
题目链接:
http://acm.hust.edu.cn/vjudge/contest/126546#problem/D
Description
After moving from his parents’ place Zhenya has been living in the University dormitory for a month.
However, he got pretty tired of the curfew time and queues to the shower room so he took a fancy for
renting an apartment. It turned out not the easiest thing in the world to make a choice. One can live in
a one bedroom apartment or in a two bedroom apartment, alone or share it with a friend. Zhenya can
afford to rent an apartment of any type alone, but he can share only a two bedroom apartment. If two
people share an apartment, each pays half of the rent. Every apartment has its own advantages like part
of the town, floor, view from the windows, etc., which Zhenya is going to take into account to make a
decision.
Besides that, his friends, he’s ready to share an apartment with, also have certain advantages. For example,
Igor is a good cook, Dima is tidy, Kostya is a good cook and at the same time can explain how to solve
functional analysis problems. And do not forget that living alone has its own bright sides.
Zhenya has already prepared the list of suitable apartments and possible housemates. Zhenya has estimated
in units the advantages of each apartment and each friend and also the advantages of living alone. Besides,
he knows the maximum sum of money he and each of his friends is ready to pay for the apartment. Help
Zhenya to make a decision.
Input
2015. Zhenya moves from the dormitory Time limit: 1.0 secondMemory limit: 64 MB After moving from hi ... Zhenya moves from parents 题目链接: http://acm.hust.edu.cn/vjudge/contest/126546#problem/C Description Z ... After moving from his parents’ place Zhenya has been living in the University dormitory for a month. ... 线段树每个结点维护两个值,分别是这个区间的 负债 和 余钱. 按时间顺序从前往后看的时候,显然负债是单调不减的. 按时间顺序从后往前看的时候,显然余钱也是单调不减的,因为之前如果有余钱,可能会增加现在 ... Zhenya moves from parents Time limit: 1.0 secondMemory limit: 64 MB Zhenya moved from his parents’ h ... 2014. Zhenya moves from parents Time limit: 1.0 secondMemory limit: 64 MB Zhenya moved from his pare ... Zhenya moved from his parents' home to study in other city. He didn't take any cash with him, he onl ... 题意:儿子身无分文出去玩,只带了一张他爸的信用卡,当他自己现金不足的时候就会用信用卡支付,然后儿子还会挣钱,挣到的钱都是现金,也就是说他如果有现金就会先花现金,但是有了现金他不会还信用卡的钱.他每花一 ... 题意:给定 n 个裁判,然后每个都一些题目,现在要从每一个按顺序去选出 k 个题,并且这 k 个要按不递减顺序,如果没有,就用50补充. 析:就按他说的来,直接模拟就好. 代码如下: #pragma ... IOS开发-你不可缺少的资源汇总-知识分享-转 如何用Facebook graphic api上传视频: http://developers.facebook.com/blog/post/532/ ... 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2818 题意:有N个块,每次有两个操作: M x y表示把x所在的那一堆全部移到y所在的那一堆的下方. ... 题目链接:http://poj.org/problem?id=2828 由于最后一个人的位置一定是不会变的,所以我们倒着做,先插入最后一个人. 我们每次处理的时候,由于已经知道了这个人的位置k,这个位 ... 使用easyui实现列表的批量删除 首先要做的就是增加一个多选框 <table id="otGrid" nowrap="false" style=&quo ... 题目 思路:edit(i, j),它表示第一个字符串的长度为i的子串到第二个字符串的长度为j的子串的编辑距离. 有如下动态规划公式: if i == 0 且 j == 0,edit(i, j) = 0 ... 我一直相信这道题有十分巧妙的解法的,去搜了好多题解发现有的太过玄妙不能领会. 最简单的就是枚举n的所有约数,然后二重循环找lcm(a, b) = n的个数 #include <cstdio> ... 当网站的访问量大了就会考虑负载均衡,这也是每一个架构师的基本功了,其基本地位就相当于相声里的说学逗唱,活好不好就看这个了 :) 传统的负载均衡思路是单点的,不管你是硬件的还是软件的基本都是这样的原理 ... javac命令初窥 注:以下红色标记的参数在下文中有所讲解. 用法: javac <options> <source files> 其中, 可能的选项包括: -g ... 做的第一道差分约束的题目,思考了一天,终于把差分约束弄懂了O(∩_∩)O哈哈~ 题意(略坑):三元组{ai,bi,ci},表示区间[ai,bi]上至少要有ci个数字相同,其实就是说,在区间[0,500 ... Leap Motion 体系架构 Leap Motion支持所有主流操作系统,leap motion在Windows系统下是作为一个服务运行的,在Mac和Linux是后台守护进程.软件通过USB线连接 ...
The first line contains three integers: the maximum sum Zhenya is ready to pay monthly, the advantages of
living alone in a one bedroom apartment and the advantages of living alone in a two bedroom apartment.
The second line contains an integer
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