leetcode@ [129] Sum Root to Leaf Numbers (DFS)

https://leetcode.com/problems/sum-root-to-leaf-numbers/

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

For example,

    1
   / \
  2   3

The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.

Return the sum = 12 + 13 = 25.

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    void travel(vector<vector<int> >& nums, vector<int>& load, TreeNode* root) {
        if(!(root->left) && !(root->right)) {
            nums.push_back(load);
            return;
        }

        if(root->left) {
            load.push_back(root->left->val);
            travel(nums, load, root->left);
            load.pop_back();
        }
        if(root->right) {
            load.push_back(root->right->val);
            travel(nums, load, root->right);
            load.pop_back();
        }
    }
    int sumNumbers(TreeNode* root) {
        if(root == NULL)  return ;

        vector<vector<int> > nums;
        vector<int> load;
        int res = ;

        load.push_back(root->val);
        travel(nums, load, root);

        for(int i=; i<nums.size(); ++i) {
            int rhs = ;
            for(int j=; j<nums[i].size(); ++j) {
                rhs = rhs *  + nums[i][j];
            }
            res += rhs;
        }
        return res;
    }
};