题目:

Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.

Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.

For the purpose of this problem, we define empty string as valid palindrome.

说明:

1)注意两点:a、判断满足条件的字符  b、大写变小写(本题认为不区分大小写)

2)字符串为空则true

实现:

 class Solution {
public:
bool isPalindrome(string s) {
if(s.empty()) return true;
int len=strlen(s.c_str());
int i=;
int j=;
for (;i<len;i++)
{
if (isChar(s[i]))//去其他符合,若有大写则大写变小写
{
s[i] = tolower(s[i]);//库函数
s[j++]=s[i];
}
}
s[j]='\0';
if (s[]=='\0') return true;
int len2=strlen(s.c_str());
i=;
while(i<=len2--i) //判断是否回文
{
if(s[i]!=s[len2--i]) return false;
i++;
}
return true;
}
private:
bool isChar(char t)//判断是否满足条件字符
{
if (('a' <= t&&t<='z')||('A' <= t&&t<='Z')||('' <= t&&t<=''))
{
return true;
}
else
return false;
}
};

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