Google Code Jam 2014 资格赛:Problem B. Cookie Clicker Alpha
Introduction
Cookie Clicker is a Javascript game by Orteil, where players click on a picture of a giant cookie. Clicking on the giant cookie gives them cookies. They can spend those cookies to buy buildings. Those buildings help them get even more cookies. Like this problem, the game is very cookie-focused. This problem has a similar idea, but it does not assume you have played Cookie Clicker. Please don't go play it now: it might be a long time before you come back.
Problem
In this problem, you start with 0 cookies. You gain cookies at a rate of 2 cookies per second, by clicking on a giant cookie. Any time you have at least C cookies, you can buy a cookie farm. Every time you buy a cookie farm, it costs you C cookies and gives you an extra F cookies per second.
Once you have X cookies that you haven't spent on farms, you win! Figure out how long it will take you to win if you use the best possible strategy.
Example
Suppose C=500.0, F=4.0 and X=2000.0. Here's how the best possible strategy plays out:
- You start with 0 cookies, but producing 2 cookies per second.
- After 250 seconds, you will have C=500 cookies and can buy a farm that producesF=4 cookies per second.
- After buying the farm, you have 0 cookies, and your total cookie production is 6 cookies per second.
- The next farm will cost 500 cookies, which you can buy after about 83.3333333seconds.
- After buying your second farm, you have 0 cookies, and your total cookie production is 10 cookies per second.
- Another farm will cost 500 cookies, while you can buy after 50 seconds.
- After buying your third farm, you have 0 cookies, and your total cookie production is 14 cookies per second.
- Another farm would cost 500 cookies, but it actually makes sense not to buy it: instead you can just wait until you have X=2000 cookies, which takes about142.8571429 seconds.
Total time: 250 + 83.3333333 + 50 + 142.8571429 = 526.1904762 seconds.
Notice that you get cookies continuously: so 0.1 seconds after the game starts you'll have 0.2 cookies, and π seconds after the game starts you'll have 2π cookies.
Input
The first line of the input gives the number of test cases, T. T lines follow. Each line contains three space-separated real-valued numbers: C, F and X, whose meanings are described earlier in the problem statement.
C, F and X will each consist of at least 1 digit followed by 1 decimal point followed by from 1 to 5 digits. There will be no leading zeroes.
Output
For each test case, output one line containing "Case #x: y", where x is the test case number (starting from 1) and y is the minimum number of seconds it takes before you can have X delicious cookies.
We recommend outputting y to 7 decimal places, but it is not required. y will be considered correct if it is close enough to the correct number: within an absolute or relative error of 10-6. See the FAQ for an explanation of what that means, and what formats of real numbers we accept.
Limits
1 ≤ T ≤ 100.
Small dataset
1 ≤ C ≤ 500.
1 ≤ F ≤ 4.
1 ≤ X ≤ 2000.
Large dataset
1 ≤ C ≤ 10000.
1 ≤ F ≤ 100.
1 ≤ X ≤ 100000.
Sample
Input
Output
4
30.0 1.0 2.0
30.0 2.0 100.0
30.50000 3.14159 1999.19990
500.0 4.0 2000.0
Case #1: 1.0000000
Case #2: 39.1666667
Case #3: 63.9680013
Case #4: 526.1904762
Note
Cookie Clicker was created by Orteil. Orteil does not endorse and has no involvement with Google Code Jam.
Google Code Jam 2014 资格赛:Problem B. Cookie Clicker Alpha的更多相关文章
- Google Code Jam 2014 资格赛:Problem D. Deceitful War
This problem is the hardest problem to understand in this round. If you are new to Code Jam, you sho ...
- Google Code Jam 2014 资格赛:Problem C. Minesweeper Master
Problem Minesweeper is a computer game that became popular in the 1980s, and is still included in so ...
- Google Code Jam 2014 Qualification 题解
拿下 ABD, 顺利晋级, 预赛的时候C没有仔细想,推荐C题,一个非常不错的构造题目! A Magic Trick 简单的题目来取得集合的交并 1: #include <iostream> ...
- Google Code Jam 2014 Round 1 A:Problem C. Proper Shuffle
Problem A permutation of size N is a sequence of N numbers, each between 0 and N-1, where each numbe ...
- Google Code Jam 2014 Round 1 A:Problem A Charging Chaos
Problem Shota the farmer has a problem. He has just moved into his newly built farmhouse, but it tur ...
- Google Code Jam 2014 Round 1 A:Problem B. Full Binary Tree
Problem A tree is a connected graph with no cycles. A rooted tree is a tree in which one special ver ...
- Google Code Jam 2014 Round 1B Problem B
二进制数位DP,涉及到数字的按位与操作. 查看官方解题报告 #include <cstdio> #include <cstdlib> #include <cstring& ...
- Google Code Jam 2014 总结
第一次参加ACM竞赛,对自己取得的成绩还满意. Round1A: Rank: 2446 Score: 9 (没有进前1000名,只能拼下次了) Round1B: Rank: 944 Score: 42 ...
- [Google Code Jam (Qualification Round 2014) ] B. Cookie Clicker Alpha
Problem B. Cookie Clicker Alpha Introduction Cookie Clicker is a Javascript game by Orteil, where ...
随机推荐
- socket 和 webservice 的区别和比较
时间紧迫,我就直奔主题. 目前需要说服客户使用webservice 而不是socket. 我觉得要先分别解释下什么是socket 什么是webservice..这个要我该怎么说才比较形象,让人一定就明 ...
- [Contest20180418]数学竞赛
题意:初始时$x=0$(长度),当$x$为长度时,你可以把$x$变成$\sin^{-1}x,\cos^{-1}x,\tan^{-1}x$之一($x$变为角度),若$x$为角度,你可以把$x$变成$\s ...
- nodejs处理高并发问题
做了一个nodejs并发测试,先描述一下环境 数据库mysql,大概两张表,读取第一张表test的数据,拿出来-1,存到第二张testlog表记录一下,用jmeter同事模拟50个请求,结果发现, ...
- python核心编程学习记录之正则表达式
- Python-爬虫-针对有frame框架的页面
有的页面会使用frame 框架,使用Selenium + PhantomJS 后并不会加载iframe 框架中的网页内容.iframe 框架相当于在页面中又加载了一个页面,需要使用Selenium 的 ...
- 联想Y430P CentOS 7.3 无线网络的配置
# uname -a # 查看内核/操作系统/CPU信息的Linux系统信息命令 [root@www ~]# uname -a Linux www SMP Tue Nov :: UTC x86_64 ...
- Html5 Canvas之arc函数图示详解
在不变换坐标系的情况下,arc函数画弧的方向如下图所示: 举例来说,arc(x,y,r,Math.PI/6,Math.PI/3,false);是以x,y为圆心,r为半径,从x正轴顺时针30度为起始角, ...
- C# Redis Server分布式缓存编程(一)
这篇文章我将介绍如果用最简洁的方式配置Redis Server, 以及如何使用C#和它交互编程 一. 背景介绍 Redis是最快的key-value分布式缓存之一 缺点: 没有本地数据缓冲, 目前还没 ...
- vsftpd 配置:chroot_local_user与chroot_list_enable userlist_enable userlist_deny详解
默认情况下,如果设置了 userlist_enable=YES,当 userlist_deny 选项设置为 YES 的时候,userlist_file=/etc/vsftpd.userlist 中列出 ...
- 斯坦福《机器学习》Lesson4感想--1、Logistic回归中的牛顿方法
在上一篇中提到的Logistic回归是利用最大似然概率的思想和梯度上升算法确定θ,从而确定f(θ).本篇将介绍还有一种求解最大似然概率ℓ(θ)的方法,即牛顿迭代法. 在牛顿迭代法中.如果一个函数是,求 ...