Python 常用的操作文件代码

1：统计list中相同的个数，并按大小排序。

original_list = ['a', 'b', 'b', 'a', 'd', 'd', 'b', 'z', 'c', 'b', 'r', 's', 'h', 'f', 'f', 's', 'b', 'b', 'y', 'b']
counter = {}
for i in original_list:
    if original_list.count(i) > 1:
        counter[i] = original_list.count(i)

# 按字典的值，进行从大到排序
counter_list = list(zip(counter.values(), counter.keys()))
counter1_list = sorted(counter_list, reverse=True)

# # 按字典的键，进行从大到排序
# counter1 = sorted(counter.items(), key=lambda x: x[0], reverse=True)

for counter1 in counter1_list:
    print(counter1)

2：读取excel中某一个sheet中的每一行数据。

import xlrd
excel_path = r'********'
data = xlrd.open_workbook(excel_path).sheet_by_name("sheet1")
n_rows = data.nrows  # 行数
for i in range(0, n_rows):
    # 每一行数据
    row_values = data.row_values(i)
    print(row_values)

3：存储数据到excel。

import pandas as pd
dict_content_list = [{'a': '', 'b': ''}, {'a': '', 'b': ''}]
data = pd.DataFrame(dict_content_list)
data.to_excel('./***.xls', encoding='utf8', index=False)

 4：统计list中相同元素的个数，并从大到小排序。

a_list = ['', '', '', '', '', '', '', '']
counter = {}
for i in a_list:
    if a_list.count(i) > 0:
        counter[i] = a.count(i)

# 按字典的值，进行从大到排序
counter_list = list(zip(counter.values(), counter.keys()))
counter1_list = sorted(counter_list, reverse=True)
# # 按字典的键，进行从大到排序
# counter1 = sorted(counter.items(), key=lambda x: x[0], reverse=True)

for counter1 in counter1_list:
    print(counter1)

5：存储数据到CSV。

import csv
test_list = ['a', 'b', 'c']
with open(f'test.csv', "a+", encoding='utf-8', newline='') as f:
    writer = csv.writer(f, dialect="excel")
    writer.writerow(test_list)

6：读取excel数据存储到mongodb。

import pymongo
import xlrd
client = pymongo.MongoClient(host='192.168.0.193', port=27017)
db_storage = client.liuxue['liuxue']
excel_path = r'C:\Users\Administrator\Desktop\留学.xlsx'
data = xlrd.open_workbook(excel_path).sheets()[0]
# 读取excel第一行数据作为存入mongodb的字段名
rows_tag = data.row_values(0)
n_rows = data.nrows
for i in range(1, n_rows):
    # 将字段名和excel数据存储为字典形式
    result_dict = dict(zip(rows_tag, data.row_values(i)))
    print(result_dict)
    db_storage.insert_one(result_dict)

7：字典键获值按大小排序。

counter = {}
# 按字典的值，进行从大到排序
counter_list = list(zip(counter.values(), counter.keys()))
counter1_list = sorted(counter_list, reverse=True)
# 按字典的键，进行从大到排序
counter1 = sorted(counter.items(), key=lambda x: x[0], reverse=True)