B. Dasha and friends
time limit per test:2 seconds
memory limit per test:256 megabytes
input:standard input
output:standard output

Running with barriers on the circle track is very popular in the country where Dasha lives, so no wonder that on her way to classes she saw the following situation:

The track is the circle with length L, in distinct points of which there are n barriers. Athlete always run the track in counterclockwise direction if you look on him from above. All barriers are located at integer distance from each other along the track.

Her friends the parrot Kefa and the leopard Sasha participated in competitions and each of them ran one lap. Each of the friends started from some integral point on the track. Both friends wrote the distance from their start along the track to each of the n barriers. Thus, each of them wrote n integers in the ascending order, each of them was between 0 and L - 1, inclusively.

Consider an example. Let L = 8, blue points are barriers, and green points are Kefa's start (A) and Sasha's start (B). Then Kefa writes down the sequence[2, 4, 6], and Sasha writes down [1, 5, 7].

There are several tracks in the country, all of them have same length and same number of barriers, but the positions of the barriers can differ among different tracks. Now Dasha is interested if it is possible that Kefa and Sasha ran the same track or they participated on different tracks.

Write the program which will check that Kefa's and Sasha's tracks coincide (it means that one can be obtained from the other by changing the start position). Note that they always run the track in one direction — counterclockwise, if you look on a track from above.

Input

The first line contains two integers n and L (1 ≤ n ≤ 50, n ≤ L ≤ 100) — the number of barriers on a track and its length.

The second line contains n distinct integers in the ascending order — the distance from Kefa's start to each barrier in the order of its appearance. All integers are in the range from 0 to L - 1 inclusively.

The second line contains n distinct integers in the ascending order — the distance from Sasha's start to each barrier in the order of its overcoming. All integers are in the range from 0 to L - 1 inclusively.

Output

Print "YES" (without quotes), if Kefa and Sasha ran the coinciding tracks (it means that the position of all barriers coincides, if they start running from the same points on the track). Otherwise print "NO" (without quotes).

Examples
input
3 8
2 4 6
1 5 7
output
YES
input
4 9
2 3 5 8
0 1 3 6
output
YES
input
2 4
1 3
1 2
output
NO
Note

The first test is analyzed in the statement.

题意:给你一个环,然后让你安排A的起点和B的起点,使得某些特殊点到A的距离是a[i],某些点到B的距离是b[i],问你可不可行。

题解:暴力搜一遍

#include <iostream>
#include<cstdio>
using namespace std;
int n,l;
int a[],b[];
int main()
{
scanf("%d%d",&n,&l);
for(int i=;i<=n;i++) scanf("%d",&a[i]);
for(int i=;i<=n;i++) scanf("%d",&b[i]);
bool flag;
for(int i=;i<=n;i++)
{
int start=(a[i]-b[]+l)%l;
flag=;
for(int j=;j<=n;j++)//假设A的起点为0坐标
{
if (a[(i+j-)%n+]!=(start+b[j])%l) {flag=;break;}
}
if (flag) break;
}
if (flag) printf("YES\n"); else printf("NO\n");
return ;
}

Codeforces Round #394 (Div. 2) B. Dasha and friends的更多相关文章

  1. Codeforces Round #394 (Div. 2) E. Dasha and Puzzle(分形)

    E. Dasha and Puzzle time limit per test 2 seconds memory limit per test 256 megabytes input standard ...

  2. Codeforces Round #394 (Div. 2) E. Dasha and Puzzle 构造

    E. Dasha and Puzzle 题目连接: http://codeforces.com/contest/761/problem/E Description Dasha decided to h ...

  3. Codeforces Round #394 (Div. 2) D. Dasha and Very Difficult Problem 贪心

    D. Dasha and Very Difficult Problem 题目连接: http://codeforces.com/contest/761/problem/D Description Da ...

  4. Codeforces Round #394 (Div. 2) C. Dasha and Password 暴力

    C. Dasha and Password 题目连接: http://codeforces.com/contest/761/problem/C Description After overcoming ...

  5. Codeforces Round #394 (Div. 2) B. Dasha and friends 暴力

    B. Dasha and friends 题目连接: http://codeforces.com/contest/761/problem/B Description Running with barr ...

  6. Codeforces Round #394 (Div. 2) A. Dasha and Stairs 水题

    A. Dasha and Stairs 题目连接: http://codeforces.com/contest/761/problem/A Description On her way to prog ...

  7. Codeforces Round #394 (Div. 2) D. Dasha and Very Difficult Problem —— 贪心

    题目链接:http://codeforces.com/contest/761/problem/D D. Dasha and Very Difficult Problem time limit per ...

  8. Codeforces Round #394 (Div. 2) C. Dasha and Password —— 枚举

    题目链接:http://codeforces.com/problemset/problem/761/C C. Dasha and Password time limit per test 2 seco ...

  9. Codeforces Round #394 (Div. 2) B. Dasha and friends —— 暴力 or 最小表示法

    题目链接:http://codeforces.com/contest/761/problem/B B. Dasha and friends time limit per test 2 seconds ...

  10. Codeforces Round #394 (Div. 2) C. Dasha and Password

    C. Dasha and Password time limit per test 2 seconds memory limit per test 256 megabytes input standa ...

随机推荐

  1. Django - 权限(1)

    一.权限表结构设计 1.认识权限 生活中处处有权限,比如,腾讯视频开会员才有观看某个最新电影的权限,你有房间钥匙就有了进入这个房间的权限,等等.同样,程序开发过程中也有权限,我们今天说的权限指的是we ...

  2. 学习笔记のsendRedirect &forward

    尽管HttpServletResponse.sendRedirect方法和RequestDispatcher.forward方法都可以让浏览器获得另外一个URL所指向的资源,但两者的内部运行机制有着很 ...

  3. C#多线程同步案例实操

    好久没有写博客了,为了养成学习的习惯,培养积极年轻的心态,又回到了博客园这个平台继续撸起时隔多年未光顾的空间. 项目需求: 实现一个简单的获取始发目的耗时.距离,将结果输出表格. 方案思路: 通过多线 ...

  4. 微信小程序组件button

    表单组件button:官方文档 Demo Code: var types=['default', 'primary', 'warn']; var pageObject = { data: { defa ...

  5. Java分布式:JWT(JSON Web Tokens)

    Java分布式:JWT(JSON Web Tokens) 0.优势 Session方式存储用户状态占用大量服务器内存.一般而言,大型应用还需要借助一些KV数据库和一系列缓存机制来实现Session的存 ...

  6. 微信小程序 使用腾讯地图SDK详解及实现步骤

    信小程序 使用腾讯地图SDK详解及实现步骤    微信小程序JavaScript SDK: 官方文档:http://lbs.qq.com/qqmap_wx_jssdk/index.html 步骤: 1 ...

  7. 安装三大浏览器驱动driver

    1.chromedriver 下载地址:https://code.google.com/p/chromedriver/downloads/list 2.Firefox的驱动geckodriver 下载 ...

  8. LeetCode: Find Largest Value in Each Tree Row

    BFS /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * ...

  9. Building an FTP Test Plan

    参考:http://jmeter.apache.org/usermanual/build-ftp-test-plan.html 1.创建一个线程组 2.线程组--->添加--->配置元件- ...

  10. node第一个程序

    var http = require('http') var url = require('url') var fs=require("fs") var router = requ ...