LeetCode——Hamming Distance

Question

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given two integers x and y, calculate the Hamming distance.

Note:

0 ≤ x, y < 2^31.

Example:

Input: x = 1, y = 4

Output: 2

Explanation:

1 (0 0 0 1)

4 (0 1 0 0)

The above arrows point to positions where the corresponding bits are different.

具体实现

class Solution {
public:
int hammingDistance(int x, int y) {
int tmp = x ^ y;
int res = 0;
while (tmp > 0) {
if (tmp % 2 != 0)
res++;
tmp = tmp >> 1;
}
return res;
}
};

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