680. Valid Palindrome II【Easy】【双指针-可以删除一个字符,判断是否能构成回文字符串】
Given a non-empty string s
, you may delete at most one character. Judge whether you can make it a palindrome.
Example 1:
Input: "aba"
Output: True
Example 2:
Input: "abca"
Output: True
Explanation: You could delete the character 'c'.
Note:
- The string will only contain lowercase characters a-z. The maximum length of the string is 50000.
class Solution {
public boolean validPalindrome(String s) {
int i = -1, j = s.length();
while(++i < --j) {
if(s.charAt(i) != s.charAt(j))
return isPalindrome(s,i+1,j) || isPalindrome(s,i,j-1);
}
return true;
}
private boolean isPalindrome(String s, int i, int j) {
while(i < j) {
if(s.charAt(i++) != s.charAt(j--)) return false;
}
return true;
}
}
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