POJ 2686 Traveling by Stagecoach

状压DP

dp[s][p]用了哪几张票，到哪个节点的最小费用。

注意：G++ %.3lf输出会WA，但C++能过；改成%.3f，C++，G++都能AC

#include<cstdio>
#include<cstring>
#include<cmath>
#include<queue>
#include<vector>
#include<map>
#include<algorithm>
using namespace std;

const double INF = ;
int n, m, p, a, b;
int t[];
struct Edge
{
    int to;
    int dis;
}e[];
int tot;
vector<int>g[];
double dp[][];

int main()
{
    while (~scanf("%d%d%d%d%d", &n, &m, &p, &a, &b))
    {
        if (n ==  && m ==  && p ==  && a ==  && b == ) break;

        tot = ;
        for (int i = ; i <= m; i++) g[i].clear();
        for (int i = ; i < ( << n); i++)
            for (int j = ; j <= m; j++) dp[i][j] = INF;

        for (int i = ; i < n; i++) scanf("%d", &t[i]);
        for (int i = ; i <= p; i++)
        {
            int u, v, c; scanf("%d%d%d", &u, &v, &c);
            e[++tot].to = v; e[tot].dis = c; g[u].push_back(tot);
            e[++tot].to = u; e[tot].dis = c; g[v].push_back(tot);
        }

        dp[][a] = ;
        for (int i = ; i < ( << n); i++)
        {
            for (int j = ; j <= m; j++)
            {
                if (dp[i][j] == INF) continue;
                for (int k = ; k < n; k++)
                {
                    if ((i | ( << k)) == i) continue;
                    for (int s = ; s < g[j].size(); s++)
                    {
                        dp[(i | ( << k))][e[g[j][s]].to] = min(
                            dp[(i | ( << k))][e[g[j][s]].to],
                            dp[i][j] + 1.0*e[g[j][s]].dis / (1.0*t[k]));
                    }
                }
            }
        }

        double ans = INF;
        for (int i = ; i < ( << n); i++)
            ans = min(ans, dp[i][b]);
        if (ans == INF) printf("Impossible\n");
        else printf("%.3f\n", ans);
    }
    return ;
}