[LC] 541. Reverse String II
Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or equal to k characters, then reverse the first k characters and left the other as original.
Example:
Input: s = "abcdefg", k = 2
Output: "bacdfeg"
Restrictions:
- The string consists of lower English letters only.
- Length of the given string and k will in the range [1, 10000]
class Solution {
public String reverseStr(String s, int k) {
int i = 0;
char[] charArr = s.toCharArray();
while (i < charArr.length) {
int j = Math.min(i + k - 1, charArr.length - 1);
swap(i, j, charArr);
i += 2 * k;
}
return new String(charArr);
}
private void swap(int i, int j, char[] charArr) {
while (i < j) {
char temp = charArr[i];
charArr[i] = charArr[j];
charArr[j] = temp;
i += 1;
j -= 1;
}
}
}
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