Elevator poj3539
| Time Limit: 4000MS | Memory Limit: 65536K | |
| Total Submissions: 1072 | Accepted: 287 | |
| Case Time Limit: 2000MS | ||
Description
Edward works as an engineer for Non-trivial Elevators: Engineering, Research and Construction (NEERC). His new task is to design a brand new elevator for a skyscraper with h floors.
Edward has an idée fixe: he thinks that four buttons are enough to control the movement of the elevator. His last proposal suggests the following four buttons:
- Move a floors up.
- Move b floors up.
- Move c floors up.
- Return to the first floor.
Initially, the elevator is on the first floor. A passenger uses the first three buttons to reach the floor she needs. If a passenger tries to move a, b or c floors up and there is no such floor (she attempts to move higher than the h-th floor), the elevator doesn’t move.
To prove his plan worthy, Edward wants to know how many floors are actually accessible from the first floor via his elevator. Help him calculate this number.
Input
The first line of the input file contains one integer h — the height of the skyscraper (1 ≤ h ≤ 1018).
The second line contains three integers a, b and c — the parameters of the buttons (1 ≤ a, b, c ≤ 100 000).
Output
Output one integer number — the number of floors that are reachable from the first floor.
Sample Input
15
4 7 9
Sample Output
9
#include <iostream>
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <vector>
#include <queue>
using namespace std;
#define ll long long
ll bb[];
ll a,b,c;
priority_queue<ll,vector<ll>,greater<ll> > q;
void bfs()
{
while(!q.empty())q.pop();
q.push(+a),q.push(+b),q.push(+c);
ll d,i=;
while(!q.empty())
{
d=q.top();
q.pop();
if(bb[d%a]!=-&&bb[d%a]<=d)continue;
bb[d%a]=d;
i++;
if(i==a)return ;
q.push(d+b);
q.push(d+c);
}
}
int main()
{
ll h,ans;
ll i;
while(~scanf("%I64d",&h))
{
scanf("%I64d%I64d%I64d",&a,&b,&c);
if(a>b)swap(a,b);
if(a>c)swap(a,c);
memset(bb,-,sizeof(bb));
bfs();
ans=;
for(i=; i<a; i++)
{
// cout<<bb[i]<<" ";
if(bb[i]==-||h<bb[i])continue;
ans+=(h-bb[i]+)/a;
if((h-bb[i]+)%a)ans++;
}
// cout<<endl;
printf("%I64d\n",ans+);
}
}
Elevator poj3539的更多相关文章
- POJ3539 Elevator
Time Limit: 4000MS Memory Limit: 65536KB 64bit IO Format: %lld & %llu Description Edward wor ...
- poj3539 Elevator——同余类bfs
题目:http://poj.org/problem?id=3539 题目大意是给定 a, b, c,求 1~h 内有多少个数可以被 a, b, c 通过加减法组成: 这是今天刚讲的神奇的——同余类 b ...
- HDOJ 1008. Elevator 简单模拟水题
Elevator Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Su ...
- poj[2392]space elevator
Description The cows are going to space! They plan to achieve orbit by building a sort of space elev ...
- Design Elevator
From: https://discuss.leetcode.com/topic/89/write-elevator-program-using-event-driven-programming/9 ...
- PAT (Advanced Level) Practise:1008. Elevator
[题目链接] The highest building in our city has only one elevator. A request list is made up with N posi ...
- Pair Project: Elevator Scheduler [电梯调度算法的实现和测试]
作业提交时间:10月9日上课前. Design and implement an Elevator Scheduler to aim for both correctness and performa ...
- POJ2392Space Elevator(贪心+背包)
Space Elevator Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 9970 Accepted: 4738 De ...
- hdu 1008 Elevator
Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Description The hig ...
随机推荐
- 【JSP】JSP Action动作标签
Action动作标签简述 JSP action是JSP技术体系内置的一组标签,使用无需导入,或者添加另外的库.JSP action标签都是对Java代码的逻辑的封装.主要使用的是下面这些. 标签 作用 ...
- Oracle03——游标、异常、存储过程、存储函数、触发器和Java代码访问Oracle对象
作者: kent鹏 转载请注明出处: http://www.cnblogs.com/xieyupeng/p/7476717.html 1.游标(光标)Cursor 在写java程序中有集合的概念,那么 ...
- POI实现excel各种验证和导入的思路总结
制定标准 导入总是与导出相辅相成的,无规矩不成方圆.所谓的标准都是大家一同来维护和遵守的,那么首先就是制定一个模板. 这样可以减少验证的工作量. 例如时间的规范[yyyy-MM-dd],获取单元格 ...
- if __name__ == '__main__' 到底是何方神圣(转)
想必很多初次接触python都会见到这样一个语句,if __name__ == "__main__": 那么这个语句到底是做什么用的呢?在解释之前,首先要声明的是,不管你是多么小白 ...
- ElasticSearch和Kibana 5.X集群的安装
ElasticSearch和Kibana 5.X集群的安装 1.准备工作 1.1.下载安装包 1.2.系统的准备 2.ElasticSearch集群的安装 2.1.修改 config/elastics ...
- [js高手之路]javascript腾讯面试题学习封装一个简易的异步队列
这道js的面试题,是这样的,页面上有一个按钮,一个ul,点击按钮的时候,每隔1秒钟向ul的后面追加一个li, 一共追加10个,li的内容从0开始技术( 0, 1, 2, ....9 ),首先我们用闭包 ...
- 一、Nginx安装手册
1 nginx安装环境 nginx是C语言开发,建议在linux上运行,本教程使用Centos6.5作为安装环境. gcc 安装nginx需要先将官网下载的源码进行编译,编译依赖gcc环境,如果没有g ...
- 【小白成长撸】--Fibonacci
/*程序的版权和版本声明部分: *Copyright(c) 2016,电子科技大学本科生 *All rights reserved. *文件名:Fibonacci *程序作用:计算菲薄拉稀数列 *作者 ...
- Java学习记录 : 画板的实现
接触java不满一个月,看厚厚的java入门简直要醉,故利用实例来巩固所学知识. 画板的实现其实从原理来说超级简单,可能一会儿就完成了. 但作为一名强迫症患者,要实现和win下面的画板一样的功能还是需 ...
- 转: 深入Java虚拟机】之二:Class类文件结构
转载请注明出处:http://blog.csdn.net/ns_code/article/details/17675609 平台无关性 Java是与平台无关的语言,这得益于Java源代码编译后生成的存 ...