hdu-5867 Water problem(水题)
题目链接:
Water problem
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 23 Accepted Submission(s): 14
Do not count spaces or hyphens. For example, 342 (three hundred and forty-two) contains 23 letters and 115 (one hundred and fifteen) contains 20 letters. The use of "and" when writing out numbers is in compliance with British usage.
For each test case: There is one positive integer not greater one thousand.
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <bits/stdc++.h>
#include <stack>
#include <map> using namespace std; #define For(i,j,n) for(int i=j;i<=n;i++)
#define mst(ss,b) memset(ss,b,sizeof(ss)); typedef long long LL; template<class T> void read(T&num) {
char CH; bool F=false;
for(CH=getchar();CH<'0'||CH>'9';F= CH=='-',CH=getchar());
for(num=0;CH>='0'&&CH<='9';num=num*10+CH-'0',CH=getchar());
F && (num=-num);
}
int stk[70], tp;
template<class T> inline void print(T p) {
if(!p) { puts("0"); return; }
while(p) stk[++ tp] = p%10, p/=10;
while(tp) putchar(stk[tp--] + '0');
putchar('\n');
} const LL mod=1e9+7;
const double PI=acos(-1.0);
const int inf=1e9;
const int N=5e5+10;
const int maxn=(1<<20)+14;
const double eps=1e-12; int dp[1100]; int check(int x)
{
if(x<=10)
{
if(x==1||x==2||x==6||x==10)return 3;
else if(x==3||x==7||x==8)return 5;
else if(x==4||x==5||x==9)return 4;
}
else if(x<=20)
{
if(x==11||x==12||x==20)return 6;
if(x==13||x==14||x==18||x==19)return 8;
if(x==15||x==16)return 7;
if(x==17)return 9;
}
else if(x<100)
{
if(x%10==0)
{
if(x==30||x==80||x==90)return 6;
else if(x==40||x==50||x==60)return 5;
else if(x==70)return 7;
}
else return check(x%10)+check(x-x%10);
}
else if(x<1000)
{
if(x%100==0)return check(x/100)+7;
else return check(x/100)+10+check(x-(x/100)*100);
}
else return 11;
}
inline void Init()
{
for(int i=1;i<=1000;i++)
{
dp[i]=dp[i-1]+check(i);
}
} int main()
{
int t;
Init();
read(t);
while(t--)
{
int n;
read(n);
print(dp[n]);
}
return 0;
}
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