++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

给定一个二叉树,找出他的最小的深度。

最小的深度,指的是从根节点到叶子节点的,经历的最多的节点个数。

++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
test.cpp:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
 
#include <iostream>
#include <cstdio>
#include <stack>
#include <vector>
#include <queue>
#include "BinaryTree.h"

using namespace std;

int maxDepth(TreeNode *root)
{
    if(root == NULL)
    {
        return 0;
    }
    /*用队列来模拟广度优先搜索*/
    queue<TreeNode *> que;
    que.push(root);
    int count = 1;
    int depth = 0;
    while(!que.empty())
    {
        TreeNode *tmp = que.front();
        que.pop();
        count --;

if(tmp->left != NULL)
        {
            que.push(tmp->left);
        }
        if(tmp->right != NULL)
        {
            que.push(tmp->right);
        }
        if(count == 0)
        {
            depth ++;
            count = que.size();
        }
    }
    return depth;
}

// 树中结点含有分叉,
//                  8
//              /       \
//             6         1
//           /   \
//          9     2
//               / \
//              4   7
int main()
{
    TreeNode *pNodeA1 = CreateBinaryTreeNode(8);
    TreeNode *pNodeA2 = CreateBinaryTreeNode(6);
    TreeNode *pNodeA3 = CreateBinaryTreeNode(1);
    TreeNode *pNodeA4 = CreateBinaryTreeNode(9);
    TreeNode *pNodeA5 = CreateBinaryTreeNode(2);
    TreeNode *pNodeA6 = CreateBinaryTreeNode(4);
    TreeNode *pNodeA7 = CreateBinaryTreeNode(7);

ConnectTreeNodes(pNodeA1, pNodeA2, pNodeA3);
    ConnectTreeNodes(pNodeA2, pNodeA4, pNodeA5);
    ConnectTreeNodes(pNodeA5, pNodeA6, pNodeA7);

cout << maxDepth(pNodeA1) << endl;

DestroyTree(pNodeA1);
    return 0;
}

结果输出:
4
 
BinaryTree.h:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
 
#ifndef _BINARY_TREE_H_
#define _BINARY_TREE_H_

struct TreeNode
{
    int val;
    TreeNode *left;
    TreeNode *right;
    TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};

TreeNode *CreateBinaryTreeNode(int value);
void ConnectTreeNodes(TreeNode *pParent,
                      TreeNode *pLeft, TreeNode *pRight);
void PrintTreeNode(TreeNode *pNode);
void PrintTree(TreeNode *pRoot);
void DestroyTree(TreeNode *pRoot);

#endif /*_BINARY_TREE_H_*/

BinaryTree.cpp:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
 
#include <iostream>
#include <cstdio>
#include "BinaryTree.h"

using namespace std;

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */

//创建结点
TreeNode *CreateBinaryTreeNode(int value)
{
    TreeNode *pNode = new TreeNode(value);

return pNode;
}

//连接结点
void ConnectTreeNodes(TreeNode *pParent, TreeNode *pLeft, TreeNode *pRight)
{
    if(pParent != NULL)
    {
        pParent->left = pLeft;
        pParent->right = pRight;
    }
}

//打印节点内容以及左右子结点内容
void PrintTreeNode(TreeNode *pNode)
{
    if(pNode != NULL)
    {
        printf("value of this node is: %d\n", pNode->val);

if(pNode->left != NULL)
            printf("value of its left child is: %d.\n", pNode->left->val);
        else
            printf("left child is null.\n");

if(pNode->right != NULL)
            printf("value of its right child is: %d.\n", pNode->right->val);
        else
            printf("right child is null.\n");
    }
    else
    {
        printf("this node is null.\n");
    }

printf("\n");
}

//前序遍历递归方法打印结点内容
void PrintTree(TreeNode *pRoot)
{
    PrintTreeNode(pRoot);

if(pRoot != NULL)
    {
        if(pRoot->left != NULL)
            PrintTree(pRoot->left);

if(pRoot->right != NULL)
            PrintTree(pRoot->right);
    }
}

void DestroyTree(TreeNode *pRoot)
{
    if(pRoot != NULL)
    {
        TreeNode *pLeft = pRoot->left;
        TreeNode *pRight = pRoot->right;

delete pRoot;
        pRoot = NULL;

DestroyTree(pLeft);
        DestroyTree(pRight);
    }
}


 

【二叉树的递归】02二叉树的最大深度【Maximum Depth of Binary Tree】的更多相关文章

  1. LeetCode 104. 二叉树的最大深度(Maximum Depth of Binary Tree)

    104. 二叉树的最大深度 104. Maximum Depth of Binary Tree 题目描述 给定一个二叉树,找出其最大深度. 二叉树的深度为根节点到最远叶子节点的最长路径上的节点数. 说 ...

  2. [Swift]LeetCode104. 二叉树的最大深度 | Maximum Depth of Binary Tree

    Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the long ...

  3. [LintCode] Maximum Depth of Binary Tree 二叉树的最大深度

    Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the long ...

  4. leetcode 104 Maximum Depth of Binary Tree二叉树求深度

    Maximum Depth of Binary Tree Total Accepted: 63668 Total Submissions: 141121 My Submissions Question ...

  5. 104. Maximum Depth of Binary Tree(C++)

    104. Maximum Depth of Binary Tree Given a binary tree, find its maximum depth. The maximum depth is ...

  6. LeetCode:Minimum Depth of Binary Tree,Maximum Depth of Binary Tree

    LeetCode:Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth ...

  7. 【LeetCode练习题】Maximum Depth of Binary Tree

    Maximum Depth of Binary Tree Given a binary tree, find its maximum depth. The maximum depth is the n ...

  8. [Leetcode][JAVA] Minimum Depth of Binary Tree && Balanced Binary Tree && Maximum Depth of Binary Tree

    Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the n ...

  9. LeetCode Javascript实现 258. Add Digits 104. Maximum Depth of Binary Tree 226. Invert Binary Tree

    258. Add Digits Digit root 数根问题 /** * @param {number} num * @return {number} */ var addDigits = func ...

  10. 【LeetCode】104. Maximum Depth of Binary Tree (2 solutions)

    Maximum Depth of Binary Tree  Given a binary tree, find its maximum depth. The maximum depth is the ...

随机推荐

  1. Android数据适配器(Adapter)优化:使用高效的ViewHolder

    原文链接:http://stackvoid.com/using-adapter-in-efficiency-way/ 在使用Listview或GridView的时候,往往须要自己定义数据适配器.一般都 ...

  2. 查看apache,nginx,mysql,linux,php版本

    查看apache版本 /usr/sbin/apachectl -v httpd -v 安装目录,使用apachectl -v mysql版本查看 mysql -V 查看linux版本 1.cat /e ...

  3. The following classes could not be found: - android.support.v7.internal.widget.ActionBarOverlayLayout

    升级android-studio之后,出现这个问题,一直解决不了. 无意间,在布局文件的Design界面中,修改原来的AppTheme为Base.Theme.AppCompat就修复了此问题. 暂时不 ...

  4. python利用正则表达式提取字符串

    前言 正则表达式的基础知识就不说了,有兴趣的可以点击这里,提取一般分两种情况,一种是提取在文本中提取单个位置的字符串,另一种是提取连续多个位置的字符串.日志分析会遇到这种情况,下面我会分别讲一下对应的 ...

  5. java上传文件,下载文件

    1.上传文件 1 protected int doTask(BaseForm form) throws AppException, FatalException, NoExistsException, ...

  6. win7旗舰版 安装IIS中出现的问题

    最好先安装IIS成功了,再安装VS2010或者别的版本 1.hppt 错误500.19,-Internal server erroe,无法访问的请求野蛮,因为该页的相关配置数据无效,HTTP Erro ...

  7. R语言set.seed()函数介绍

    set.seed(),该命令的作用是设定生成随机数的种子,种子是为了让结果具有重复性.如果不设定种子,生成的随机数无法重现.这个函数的主要目的,是让你的模拟能够可重复出现,因为很多时候我们需要取随机数 ...

  8. iOS 尝试用 block 闭包 去代替delegate 实现方法

    通常都是这样创建alert 再加一个代理 // 创建一个UIAlertView并显示出来 UIAlertView *alertview = [[UIAlertView alloc] initWithT ...

  9. flask初次搭建rest服务笔记

    官网中有用的记录一下,太多只是记录了最简单的官网docs:http://flask.pocoo.org/docs/0.12/ 跑起来一个程序 $ export FLASK_APP=hello.py $ ...

  10. 【leetcode刷题笔记】Subsets

    Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be ...