九度OJ 1001：A+B for Matrices

时间限制：1 秒

内存限制：32 兆

特殊判题：否

提交：17682

解决：7079

题目描述：

This time, you are supposed to find A+B where A and B are two matrices, and then count the number of zero rows and columns.

输入：

The input consists of several test cases, each starts with a pair of positive integers M and N (≤10) which are the number of rows and columns of the matrices, respectively. Then 2*M lines follow, each contains N integers
in [-100, 100], separated by a space. The first M lines correspond to the elements of A and the second M lines to that of B.

The input is terminated by a zero M and that case must NOT be processed.

输出：

For each test case you should output in one line the total number of zero rows and columns of A+B.

样例输入：

2 2
1 1
1 1
-1 -1
10 9
2 3
1 2 3
4 5 6
-1 -2 -3
-4 -5 -6
0

样例输出：

1
5

来源：

2011年浙江大学计算机及软件工程研究生机试真题

思路：

本题的意思是计算两个矩阵的和中， 全0行和全0列的个数。

代码：

#include <stdio.h>

#define N 10

int main(void)
{
    int m, n, i, j;
    int a[N][N], b[N][N];

    while (scanf("%d", &m) != EOF)
    {
        if (m == 0)
            break;

        scanf("%d", &n);
        for(i=0; i<m; i++)
        {
            for(j=0; j<n; j++)
            {
                scanf("%d", &a[i][j]);
            }
        }
        int count = 0;
        for(i=0; i<m; i++)
        {
            int zerorow = 1;
            for(j=0; j<n; j++)
            {
                scanf("%d", &b[i][j]);
                a[i][j] += b[i][j];
                if (a[i][j] != 0)
                    zerorow = 0;
            }
            count += zerorow;
        }
        for(j=0; j<n; j++)
        {
            int zerocol = 1;
            for(i=0; i<m; i++)
            {
                if (a[i][j] != 0)
                    zerocol = 0;
            }
            count += zerocol;
        }

        printf("%d\n", count);
    }

    return 0;
}
/**************************************************************
    Problem: 1001
    User: liangrx06
    Language: C
    Result: Accepted
    Time:0 ms
    Memory:912 kb
****************************************************************/