洛谷 P3078 [USACO13MAR]扑克牌型Poker Hands
题目描述
Bessie and her friends are playing a unique version of poker involving a deck with N (1 <= N <= 100,000) different ranks, conveniently numbered 1..N (a normal deck has N = 13). In this game, there is only one type of hand the cows can play: one may choose a card labeled i and a card labeled j and play one card of every value from i to j. This type of hand is called a "straight".
Bessie's hand currently holds a_i cards of rank i (0 <= a_i <= 100000). Help her find the minimum number of hands she must play to get rid of all her cards.
一个牛有N堆牌,每堆排数量不等。一只牛一次可以将第i张到第j张各打一张出去,问最少几次打完
输入输出格式
输入格式:
* Line 1: The integer N.
* Lines 2..1+N: Line i+1 contains the value of a_i.
输出格式:
* Line 1: The minimum number of straights Bessie must play to get rid of all her cards.
输入输出样例
说明
Bessie can play a straight from 1 to 5, a straight from 1 to 2, a straight from 4 to 5, two straights from 2 to 2, and a straight from 5 to 5, for a total of 6 rounds necessary to get rid of all her cards.
思路:贪心即可。
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
int n;
long long ans,x,pre;
int main(){
scanf("%d%lld",&n,&x);
ans+=x;pre=x;
for(int i=;i<=n;i++){
scanf("%lld",&x);
if(x>pre) ans+=x-pre;
pre=x;
}
cout<<ans;
}
洛谷 P3078 [USACO13MAR]扑克牌型Poker Hands的更多相关文章
- 洛谷P3078 [USACO13MAR]扑克牌型Poker Hands
题目描述 Bessie and her friends are playing a unique version of poker involving a deck with \(N\) (\(1 \ ...
- P3078 [USACO13MAR]扑克牌型Poker Hands
题目描述 Bessie and her friends are playing a unique version of poker involving a deck with N (1 <= N ...
- 「Luogu P3078 [USACO13MAR]扑克牌型Poker Hands」
本题有\(O(N)\)的优秀做法,但是因为在考场上不一定能想到,就来分享一种\(O(N\log_2N)\)的做法.虽然有点慢,但是可以过. 前置芝士 线段树:提高组及以上必备内容,不会的同学可以学习一 ...
- 【贪心 思维题】[USACO13MAR]扑克牌型Poker Hands
看似区间数据结构的一道题 题目描述 Bessie and her friends are playing a unique version of poker involving a deck with ...
- 洛谷P3080 [USACO13MAR]牛跑The Cow Run
P3080 [USACO13MAR]牛跑The Cow Run 题目描述 Farmer John has forgotten to repair a hole in the fence on his ...
- 洛谷 P3079 [USACO13MAR]农场的画Farm Painting
P3079 [USACO13MAR]农场的画Farm Painting 题目描述 After several harsh winters, Farmer John has decided it is ...
- 洛谷2014选课(树型dp)
题目:https://www.luogu.org/problemnew/show/P2014 千万注意遍历 j 和 k 的边界! 0点很好用. siz很好用. #include<iostream ...
- 洛谷4951 地震 bzoj1816扑克牌 洛谷3199最小圈 / 01分数规划
洛谷4951 地震 #include<iostream> #include<cstdio> #include<algorithm> #define go(i,a,b ...
- 洛谷P2668 斗地主==codevs 4610 斗地主[NOIP 2015 day1 T3]
P2668 斗地主 326通过 2.6K提交 题目提供者洛谷OnlineJudge 标签搜索/枚举NOIp提高组2015 难度提高+/省选- 提交该题 讨论 题解 记录 最新讨论 出现未知错误是说梗啊 ...
随机推荐
- Road Construction(无向图的双连通分量)
http://poj.org/problem?id=3352 题意:给出一个有n个顶点m条边的无向连通图,问至少添加几条边,使删除任意一条边原图仍连通. 思路:一个边双连通图删除任意一条边仍为连通图. ...
- hihoCoder 数组重排
找每个位置循环节的大小. 得到结果d1, d2, ....., dn. 最终结果cmd(d1, d2, ...., dn). 水题. 题目链接: http://hihocoder.com/contes ...
- CentOS 7.0 firewall防火墙关闭firewall作为防火墙,这里改为iptables防火墙
CentOS 7.0默认使用的是firewall作为防火墙,这里改为iptables防火墙步骤: 1.先检查是否安装了: iptables service iptables status 2.安装ip ...
- scala 变量定义,基本操作符
scala是jvm语言,它将面向对象与函数风格结合的很好,它可以访问任何java类库并很好的结合使用. 它可以使程序更简单,同时可利用并发的威力. scala基本语法: package com.tes ...
- Python3之format
print('{0},{1}'.format('zhangk', 32)) print('{},{},{}'.format('zhangk','boy',32)) print('{name},{sex ...
- CSS——行业动态demo
1.padding的运用:子div继承父div的宽,子div的padding-left值是不会撑大的. 2.背景图片的运用:不平铺.定位 3.ul本身就是一个盒子,它的高度是li中的字体的默认高度撑起 ...
- c++中std::set自定义去重和排序函数
c++中的std::set,是基于红黑树的平衡二叉树的数据结构实现的一种容器,因为其中所包含的元素的值是唯一的,因此主要用于去重和排序.这篇文章的目的在于探讨和分享如何正确使用std::set实现去重 ...
- Python语言之变量2(命名规则,类型转换)
1.命名规则 1.起始位为字母(大小写)或下划线('_') 2.其他部分为字母(大小写).下划线('_')或数字(0-9) 3.大小写敏感 2.先体验一把: #Ask the user their n ...
- Shell基本运算符
原生bash不支持简单的数学运算,但是可以通过其他命令来实现,例如 awk 和 expr,expr 最常用. expr 是一款表达式计算工具,使用它能完成表达式的求值操作. 例如,两个数相加(注意使用 ...
- Altium Designer 2017 ActiveRoute使用以及其他技巧
ActiveRoute 点击右下角PCB->PCB ActiveRoute调出ActiveRoute面板 在设计电路时,有一堆细小的白色线,表示几个脚之间需要连接,按住键盘Alt + 鼠标左键, ...