HackerRank "Manasa and Prime game"
Intuitive one to learn about Grundy basic :)
Now every pile becomes a game, so we need to use Sprague-Grundy Theory. Calculation is quite intuitive - and if you print them out, you will find these Grundy numbers loops by 9.
def firstMissing(s):
ret = 0
while 1:
if ret not in s: break
else: ret += 1
return ret primes = [2,3,5,7,11,13]
def grundy(v):
if v <= 2: return 0 tmp = set([])
for p in primes:
if p >= v: break
else: tmp.add(grundy(v - p))
ret = firstMissing(tmp)
grundySet[v] = ret
return ret ####################
def simpleGrundy(v):
return [0,0,1,1,2,2,3,3,4][v%9] ####################
T = int(input())
for _ in range(T):
N = int(input())
A = map(int, input().split())
sg = map(simpleGrundy, A)
ret = 0
for g in sg: ret ^= g
print(['Sandy','Manasa'][ret!=0])
HackerRank "Manasa and Prime game"的更多相关文章
- [hackerrank]Manasa and Stones
https://www.hackerrank.com/contests/w2/challenges/manasa-and-stones 简单题. #include<iostream> us ...
- 【HackerRank】Manasa and Stones
Change language : Manasa 和 她的朋友出去徒步旅行.她发现一条小河里边顺序排列着带有数值的石头.她开始沿河而走,发现相邻两个石头上的数值增加 a 或者 b. 这条小河的尽头有一 ...
- Prime triplets (Project Euler 196)
original version hackerrank programming version 题目大意是定义了一个正整数的表,第一行是1,第二行是1,2,第三行1,2,3...定义prime tri ...
- Java 素数 prime numbers-LeetCode 204
Description: Count the number of prime numbers less than a non-negative number, n click to show more ...
- Prime Generator
Peter wants to generate some prime numbers for his cryptosystem. Help him! Your task is to generate ...
- POJ 2739. Sum of Consecutive Prime Numbers
Sum of Consecutive Prime Numbers Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 20050 ...
- UVa 524 Prime Ring Problem(回溯法)
传送门 Description A ring is composed of n (even number) circles as shown in diagram. Put natural numbe ...
- Sicily 1444: Prime Path(BFS)
题意为给出两个四位素数A.B,每次只能对A的某一位数字进行修改,使它成为另一个四位的素数,问最少经过多少操作,能使A变到B.可以直接进行BFS搜索 #include<bits/stdc++.h& ...
- hdu 5901 count prime & code vs 3223 素数密度
hdu5901题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5901 code vs 3223题目链接:http://codevs.cn/problem ...
随机推荐
- Open vSwitch安装及配置
一. Open vSwitch简介 1.1概述 Open vSwitch是一个高质量的.多层虚拟交换机,使用开源Apache 2.0许可协议,由Nicira Networks开发,主要实现代码为可移植 ...
- Maven构建web项目在Eclipse中部署的几种方法
目录: 方法一:运用Maven的plugin:jetty来部署web 方法二:运用Eclipse 的Jetty插件直接部署 方法三:运用Run on Server(tomcat)部署 [方法一].运用 ...
- Java-->将txt文件的所有行反转
--> 这里和上次代码不同,对同一文件进行操作,所以要用到一个第三方容器来存储数据 package com.dragon.java.filereverseline; import java.io ...
- CentOS6下搭建OpenVPN服务器
• OpenVPN简介 OpenVPN是一个用于创建虚拟专用网络(Virtual Private Network)加密通道的免费开源软件.使用OpenVPN可以方便地在家庭.办公场所.住宿酒店等不同网 ...
- 如何优雅的写C++代码(一)
// get the greatest power of two that is a divisor of n: return n&-n; // swap two integers a and ...
- URAL 1205 By the Underground or by Foot?(SPFA)
By the Underground or by Foot? Time limit: 1.0 secondMemory limit: 64 MB Imagine yourself in a big c ...
- IOS请求H5页面、要求自定义agent判断是电脑、安卓还是iPhone登录
//自定制的userAgent- (void)createMyAgent{ NSString *userAgent = [[[UIWebView alloc]init]stringByE ...
- Git错误non-fast-forward
Git错误non-fast-forward后的冲突解决 [日期:2012-04-21] 来源:Linux社区 作者:chain2012 [字体:大 中 小] 当要push代码到git时,出现提示 ...
- Python爬虫学习笔记——豆瓣登陆(二)
昨天能够登陆成功,但是不能使用cookies,今天试了一下requests库的Session(),发现可以保持会话了,代码只是稍作改动. #-*- coding:utf-8 -*- import re ...
- kuangbin_UnionFind B (POJ 1611)
过程是模板 merge完后扫一下几个跟0同祖先节点就是答案了 #include <iostream> #include <string> #include <cstdio ...