使用13行Python代码实现四则运算计算器函数

原创的刷新行数记录的代码，从14行到13行，是一小步也是一大步！

支持带小括号，支持多个连续+-号，如-7.9/(-1.2-++--99.3/-4.44)*---(2998.654+-+-+-(+1.3-7.654/(-1.36-99.99)/-4.33213)*-2998.13-1.31)-7.423/(-1.4235-+99.53456/-4.4)

查看计算结果的方式为：print(calculator('str格式的算式'))

 import re
 def calculator(s):
     def two_num_cal(s): # 给定str格式的两个数字（可能是整数或小数）组成的四则运算表达式，返回float型的计算结果
         if re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(2)=='*': return float(re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(1))*float(re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(3))
         elif re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(2)=='/': return float(re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(1))/float(re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(3))
         elif re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(2)=='+': return float(re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(1))+float(re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(3))
         elif re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(2)=='-': return float(re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(1))-float(re.search(r'([+-]?\d+(?:\.\d+)?)([*/+-])([+-]?\d+(?:\.\d+)?)',s).group(3))
     while not re.search(r'^[+-]?\d+(\.\d+)?$',s): # 当s不能转化为float型时，执行此while循环
         while re.search('[+-]{2,}',s): s = s.replace('++', '+').replace('--', '+').replace('+-', '-').replace('-+', '-') # 循环替换表达式中多余的+-号
         if re.search(r'[(][^()]+[)]', s): s = s[:re.search(r'[(][^()]+[)]', s).span()[0]] + str(calculator(re.search(r'[(][^()]+[)]', s).group()[1:len(re.search(r'[(][^()]+[)]', s).group())-1])) + s[re.search(r'[(][^()]+[)]', s).span()[1]:] # 匹配首个最内层小括号，递归计算其值，将结果替换至原字符串
         if re.search(r'\d+(\.\d+)?[*/][+-]?\d+(\.\d+)?', s):s = s[:re.search(r'\d+(\.\d+)?[*/][+-]?\d+(\.\d+)?', s).span()[0]] + str(two_num_cal(re.search(r'\d+(\.\d+)?[*/][+-]?\d+(\.\d+)?', s).group())) + s[re.search(r'\d+(\.\d+)?[*/][+-]?\d+(\.\d+)?', s).span()[1]:] # 匹配首个乘法或除法，将结果替换至原字符串
         if re.search(r'\d+(\.\d+)?[*/][+-]?\d+(\.\d+)?', s)==None and re.search(r'[+-]?(\d+(\.\d+)?[+-]\d+(\.\d+)?)', s): s = s[:re.search(r'[+-]?(\d+(\.\d+)?[+-]\d+(\.\d+)?)', s).span()[0]] + str(two_num_cal(re.search(r'[+-]?(\d+(\.\d+)?[+-]\d+(\.\d+)?)', s).group())) + s[re.search(r'[+-]?(\d+(\.\d+)?[+-]\d+(\.\d+)?)', s).span()[1]:] # 匹配首个加法或减法，将结果替换至原字符串
     return int(float(s)) if int(float(s))==float(s) else float(s)#如果结果能转化成int就输出int，否则输出float