UVALive 6507 Passwords
Passwords
This problem will be judged on UVALive. Original ID: 6507
64-bit integer IO format: %lld Java class name: Main

#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int maxn = ;
const int base = ;
const int mod = 1e9+;
char str[maxn][];
LL hs[maxn][],B[];
int n;
unordered_map<LL,int>ump;
void init(){
B[] = ;
for(int i = ; i < ; ++i)
B[i] = B[i-]*base%mod;
}
LL calc(int i,int L,int R){
return ((hs[i][R] - hs[i][L-]*B[R - L + ])%mod + mod)%mod;
}
void solve(){
ump.clear();
for(int i = ; i < n; ++i){
for(int j = ,len = strlen(str[i] + ); j <= len; ++j){
hs[i][j] = (hs[i][j-]*base + str[i][j])%mod;
ump[hs[i][j]]++;
}
}
int a = ,b = ;
for(int i = ; i < n; ++i){
int len = strlen(str[i] + );
for(int j = ; j <= len; ++j) --ump[hs[i][j]];
for(int j = ; j <= len; ++j){
LL suffix = calc(i,len - j + ,len);
if(!ump[suffix]) continue;
int x = ,y = ;
LL prefix = suffix;
for(int k = ; k*j <= len; ++k){
LL suffix2 = calc(i,len - j*k + ,len);
prefix = (prefix*B[j] + suffix)%mod;
if(suffix2 != prefix) break;
if(ump[prefix]) x = k;
y = k;
}
if(x == y && x == ) continue;
if(x == y) --x;
if(j*(x + y) > a + b){
a = x*j;
b = y*j;
}
}
for(int j = ; j <= len; ++j) ump[hs[i][j]]++;
}
printf("%d %d\n",a,b);
}
int main(){
int kase;
init();
scanf("%d",&kase);
while(kase--){
scanf("%d",&n);
for(int i = ; i < n; ++i)
scanf("%s",str[i] + );
solve();
}
return ;
}
/*
2
3
abcabe
defg
bcabab
*/
UVALive 6507 Passwords的更多相关文章
- UVALive - 4108 SKYLINE[线段树]
UVALive - 4108 SKYLINE Time Limit: 3000MS 64bit IO Format: %lld & %llu Submit Status uDebug ...
- UVALive - 3942 Remember the Word[树状数组]
UVALive - 3942 Remember the Word A potentiometer, or potmeter for short, is an electronic device wit ...
- UVALive - 3942 Remember the Word[Trie DP]
UVALive - 3942 Remember the Word Neal is very curious about combinatorial problems, and now here com ...
- Cracking Story - How I Cracked Over 122 Million SHA1 and MD5 Hashed Passwords
This is the story about how I cracked 122 million* password hashes with John the Ripper and oclHashc ...
- codeforces 721B B. Passwords(贪心)
题目链接: B. Passwords time limit per test 2 seconds memory limit per test 256 megabytes input standard ...
- 思维 UVALive 3708 Graveyard
题目传送门 /* 题意:本来有n个雕塑,等间距的分布在圆周上,现在多了m个雕塑,问一共要移动多少距离: 思维题:认为一个雕塑不动,视为坐标0,其他点向最近的点移动,四舍五入判断,比例最后乘会10000 ...
- UVALive 6145 Version Controlled IDE(可持久化treap、rope)
题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_ ...
- UVALive 6508 Permutation Graphs
Permutation Graphs Time Limit:3000MS Memory Limit:0KB 64bit IO Format:%lld & %llu Submit ...
- UVALive 6500 Boxes
Boxes Time Limit:3000MS Memory Limit:0KB 64bit IO Format:%lld & %llu Submit Status Pract ...
随机推荐
- TIME-April
一转眼四月份又过了三分之一,现在才开始计划自己的四月还真是对自己太过放松了呀!不过前一段时间都在搞学生会的五四评优答辩,索然不是我喜欢的过程,但是结果还比较令人欢喜.翻掉过去的篇章,展开新的一页. 四 ...
- BZOJ 1396||2865 识别子串
这个不是题解,看不懂的,别看了 明明应该是会的,怎么还是写了6个小时呢... 把后缀数组.height数组.排名数组求出来,那么对于原串s的任意子串[x,y](表示第x个到第y个字符组成的子串,字符从 ...
- Service官方教程(2)*IntentService与Service示例、onStartCommand()3个返回值的含义。
1.Creating a Started Service A started service is one that another component starts by calling start ...
- android开发学习——Mina框架
Apache Mina Server 是一个网络通信应用框架,对socket进行了封装. http://www.cnblogs.com/moonandstar08/p/5475766.html htt ...
- Android开发学习--ViewPager使用入门
ViewPager已经有了滑动的功能 activity_main.xml <?xml version="1.0" encoding="utf-8"?> ...
- [BZOJ2190][SDOI2008]仪仗队 数学
题目链接:http://www.lydsy.com/JudgeOnline/problem.php?id=2190 看到这道题首先想到了NOI2010的能量采集,这不就是赤裸裸的弱化版吗?直接上莫比乌 ...
- pandas 选择某几列
转自:https://blog.csdn.net/aaa_aaa1sdf/article/details/77414387 col_n = ['名称','收盘价','日期'] a = pd.DataF ...
- 【转】Android Activity/Fragment Lifecycle
原文来自:http://stormzhang.github.io/android/2014/08/08/activity-fragment-lifecycle/ 说Activity和Fragment是 ...
- linux centos7 tomcat8 配置成服务启动
1. tomact 解压到/usr/local/tomcat下 2.vim /usr/local/tomcat/bin/catalina.sh 在OS specific support.前加上 (注意 ...
- schtasks /create 计划任务 中文路径 名字都要加“” 子命令 /tn /tr 前面要空格 否则会出错
echo off echo. 清空连接 net use * /del /y echo. 连接 net use \\192.168.1.2\人力资源部\考勤\考勤数据-小莫提供 "密码&quo ...