python 中zip函数的使用

1.
ta = [1,2,3]
tb = [9,8,7]
tc = ['a','b','c']
for (a,b,c) in zip(ta,tb,tc):
    print(a,b,c)

2.

ta = [1,2,3]
tb = [9,8,7]

# cluster
zipped = zip(ta,tb)
print(zipped)

# decompose
na, nb = zip(*zipped)
print(na, nb)