hdoj-1212-Big Number【大数取余&简单题】

Big Number

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 6015 Accepted Submission(s): 4205

Problem Description

As we know, Big Number is always troublesome. But it's really important in our ACM. And today, your task is to write a program to calculate A mod B.



To make the problem easier, I promise that B will be smaller than 100000.



Is it too hard?

No, I work it out in 10 minutes, and my program contains less than 25 lines.

Input

The input contains several test cases. Each test case consists of two positive integers A and B. The length of A will not exceed 1000, and B will be smaller than 100000. Process to the end of file.

Output

For each test case, you have to ouput the result of A mod B.

Sample Input

2 3
12 7
152455856554521 3250

Sample Output

2
5
1521

Author

Ignatius.L

Source

杭电ACM省赛集训队选拔赛之热身赛

Recommend

Eddy | We have carefully selected several similar problems for you:
1215 1211 1210 1214

pid=1695" target="_blank">
1695

#include<stdio.h>
#include<string.h>
int main(){
	int b;
	char a[1010];
	while(~scanf("%s%d",a,&b)){
		 int len=strlen(a),res=0;
		 for(int i=0;i<len;++i){
		 	res=res*10+a[i]-'0';
		 	if(res>=b)
		 	res=res%b;
		 }
	     printf("%d\n",res);
	}
	return 0;
}