当执行计划中出现BITMAP CONVERSION TO ROWIDS关键字时,需要注意了。
前言
前些天优化了一些耗费buffers较多的SQL,但系统CPU降低的效果不明显,于是又拉了awr报告,查看了SQL ordered by Gets排名前列的SQL。
分析
SQL代码:
select distinct pro5.value as CUSTOMERCODE,
to_date('19000101000000', 'yyyymmddhh24miss') as LAST_UPDATE_TIME,
pro2.value as NAME,
nvl(pro3.value, '$$400006000004') as GENDER,
decode(pro4.value,
'$$400003000001',
decode(length(trim(pro5.value)),
18,
substr(trim(pro5.value), 7, 8)),
null) as BIRTHDAY,
decode(pro4.value, '$$400003000001', pro5.value, null) as CERT_NO,
pro4.value as CERTIFICATE_TYPE,
pro5.value as CERTIFICATE_NO,
null as NATION,
null as EFFECTIVE_DATE,
null as EXPIRE_DATE
from policy p
inner join role r
on p.topactualid = r.topactualid
and r.kind = 'INSURANCECERTIFICATELIST'
inner join property pro2
on r.topactualid = pro2.topactualid
and r.actualid = pro2.parentactualid
and r.parentagreementid = pro2.parentagreementid
and r.topagreementid = pro2.topagreementid
and pro2.kind = 'CUSTOMERNAME'
inner join property pro3
on r.topactualid = pro3.topactualid
and r.actualid = pro3.parentactualid
and r.parentagreementid = pro3.parentagreementid
and r.topagreementid = pro3.topagreementid
and pro3.kind = 'PERSONSEX'
inner join property pro4
on r.topactualid = pro4.topactualid
and r.actualid = pro4.parentactualid
and r.parentagreementid = pro4.parentagreementid
and r.topagreementid = pro4.topagreementid
and pro4.kind = 'CERTIFICATETYPE'
inner join property pro5
on r.topactualid = pro5.topactualid
and r.actualid = pro5.parentactualid
and r.parentagreementid = pro5.parentagreementid
and r.topagreementid = pro5.topagreementid
and pro5.kind = 'CERTIFICATECODE' and pro5.value is not null
left join endorsement e
on p.endorsementid = e.endorsementid
where p.productcode = '00070002'
and p.currentflag = 'Y'
and (p.uniquecode like '013100%' or p.uniquecode like '011000%')
and ((p.policystatus = '$$900001103001') or
(e.endorsementstatus = '$$900002106001' and
e.ISSUEDATE > to_date('20160411', 'YYYYMMDD')))
执行计划:
Plan hash value: 3936231819
------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 336 | 124K (1)| 00:24:55 |
| 1 | HASH UNIQUE | | 1 | 336 | 124K (1)| 00:24:55 |
| 2 | NESTED LOOPS | | 1 | 336 | 124K (1)| 00:24:55 |
| 3 | NESTED LOOPS | | 1 | 284 | 124K (1)| 00:24:55 |
| 4 | NESTED LOOPS | | 1 | 232 | 124K (1)| 00:24:55 |
| 5 | NESTED LOOPS | | 51 | 9180 | 124K (1)| 00:24:50 |
| 6 | NESTED LOOPS | | 14950 | 1868K| 11388 (1)| 00:02:17 |
|* 7 | FILTER | | | | | |
| 8 | NESTED LOOPS OUTER | | 701 | 58183 | 6559 (1)| 00:01:19 |
|* 9 | TABLE ACCESS FULL | POLICY | 2661 | 129K| 5834 (1)| 00:01:11 |
| 10 | TABLE ACCESS BY INDEX ROWID | ENDORSEMENT | 1 | 33 | 1 (0)| 00:00:01 |
|* 11 | INDEX UNIQUE SCAN | ENDORSEMENT_PK | 1 | | 0 (0)| 00:00:01 |
|* 12 | TABLE ACCESS BY INDEX ROWID | ROLE | 21 | 945 | 25 (0)| 00:00:01 |
|* 13 | INDEX RANGE SCAN | TC_ROLE66 | 453 | | 4 (0)| 00:00:01 |
|* 14 | TABLE ACCESS BY INDEX ROWID | PROPERTY | 1 | 52 | 124K (1)| 00:24:50 |
| 15 | BITMAP CONVERSION TO ROWIDS | | | | | |
| 16 | BITMAP AND | | | | | |
| 17 | BITMAP CONVERSION FROM ROWIDS| | | | | |
|* 18 | INDEX RANGE SCAN | TC_PROPERTY_PARENT | 12 | | 3 (0)| 00:00:01 |
| 19 | BITMAP CONVERSION FROM ROWIDS| | | | | |
|* 20 | INDEX RANGE SCAN | TC_PROPERTY24 | 12 | | 3 (0)| 00:00:01 |
|* 21 | TABLE ACCESS BY INDEX ROWID | PROPERTY | 1 | 52 | 13 (0)| 00:00:01 |
|* 22 | INDEX RANGE SCAN | TC_PROPERTY_PARENT | 12 | | 3 (0)| 00:00:01 |
|* 23 | TABLE ACCESS BY INDEX ROWID | PROPERTY | 1 | 52 | 3 (0)| 00:00:01 |
|* 24 | INDEX RANGE SCAN | TC_PROPERTY_PARENT | 12 | | 3 (0)| 00:00:01 |
|* 25 | TABLE ACCESS BY INDEX ROWID | PROPERTY | 1 | 52 | 3 (0)| 00:00:01 |
|* 26 | INDEX RANGE SCAN | TC_PROPERTY_PARENT | 12 | | 3 (0)| 00:00:01 |
------------------------------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
7 - filter("P"."POLICYSTATUS"='$$900001103001' OR "E"."ENDORSEMENTSTATUS"='$$900002106001' AND
"E"."ISSUEDATE">TIMESTAMP' 2016-04-11 00:00:00')
9 - filter("P"."PRODUCTCODE"='00070002' AND ("P"."UNIQUECODE" LIKE '013100%' OR "P"."UNIQUECODE"
LIKE '011000%') AND "P"."CURRENTFLAG"='Y')
11 - access("P"."ENDORSEMENTID"="E"."ENDORSEMENTID"(+))
12 - filter("R"."KIND"='INSURANCECERTIFICATELIST')
13 - access("P"."TOPACTUALID"="R"."TOPACTUALID")
14 - filter("PRO5"."VALUE" IS NOT NULL AND "PRO5"."KIND"='CERTIFICATECODE' AND
"R"."PARENTAGREEMENTID"="PRO5"."PARENTAGREEMENTID" AND "R"."TOPAGREEMENTID"="PRO5"."TOPAGREEMENTID")
18 - access("R"."ACTUALID"="PRO5"."PARENTACTUALID")
20 - access("R"."TOPACTUALID"="PRO5"."TOPACTUALID")
21 - filter("PRO2"."KIND"='CUSTOMERNAME' AND "R"."TOPACTUALID"="PRO2"."TOPACTUALID" AND
"R"."PARENTAGREEMENTID"="PRO2"."PARENTAGREEMENTID" AND "R"."TOPAGREEMENTID"="PRO2"."TOPAGREEMENTID")
22 - access("R"."ACTUALID"="PRO2"."PARENTACTUALID")
23 - filter("PRO4"."KIND"='CERTIFICATETYPE' AND "R"."TOPACTUALID"="PRO4"."TOPACTUALID" AND
"R"."PARENTAGREEMENTID"="PRO4"."PARENTAGREEMENTID" AND "R"."TOPAGREEMENTID"="PRO4"."TOPAGREEMENTID")
24 - access("R"."ACTUALID"="PRO4"."PARENTACTUALID")
25 - filter("PRO3"."KIND"='PERSONSEX' AND "R"."TOPACTUALID"="PRO3"."TOPACTUALID" AND
"R"."PARENTAGREEMENTID"="PRO3"."PARENTAGREEMENTID" AND "R"."TOPAGREEMENTID"="PRO3"."TOPAGREEMENTID")
26 - access("R"."ACTUALID"="PRO3"."PARENTACTUALID")
分析:
1)执行计划中 id = 15 关键字为BITMAP CONVERSION TO ROWIDS,此关键字在此之前都未遇见过,于是谷歌下,有了以下解释:
1)出现这样的情况,是因为表中存在不适当的索引,这些索引列的唯一度不高,oracle就有可能选择两个这样的索引转为bitmap来执行
2)根据这两个索引的值再确认共同有的ROWID,最后再通过ROWID回表提取符合条件的数据。
2) 可以使用/*+ opt_param('_b_tree_bitmap_plans','false') */hint 在sql级消除bitmap
3) 也可以删除选择率低的索引,建立复合索引进行改善
4) 根据执行计划的谓词信息,我建立了如下索引:
create index IDX_POLICY_01 on POLICY (PRODUCTCODE, CURRENTFLAG, UNIQUECODE);
create index IDX_PROPERTY_TEST02 on PROPERTY (KIND, PARENTACTUALID, TOPACTUALID, PARENTAGREEMENTID, TOPAGREEMENTID, VALUE) nologging;
5)建立索引后的执行计划:
Plan hash value: 2001935116
-----------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
-----------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 336 | 10938 (1)| 00:02:12 |
| 1 | HASH UNIQUE | | 1 | 336 | 10938 (1)| 00:02:12 |
| 2 | NESTED LOOPS | | 1 | 336 | 10937 (1)| 00:02:12 |
| 3 | NESTED LOOPS | | 1 | 284 | 10934 (1)| 00:02:12 |
| 4 | NESTED LOOPS | | 1 | 232 | 10931 (1)| 00:02:12 |
| 5 | NESTED LOOPS | | 1 | 180 | 10928 (1)| 00:02:12 |
| 6 | NESTED LOOPS | | 875 | 109K| 8301 (1)| 00:01:40 |
|* 7 | FILTER | | | | | |
| 8 | NESTED LOOPS OUTER | | 300 | 24900 | 6500 (1)| 00:01:19 |
|* 9 | TABLE ACCESS FULL | POLICY | 2776 | 135K| 5751 (1)| 00:01:10 |
| 10 | TABLE ACCESS BY INDEX ROWID| ENDORSEMENT | 1 | 33 | 1 (0)| 00:00:01 |
|* 11 | INDEX UNIQUE SCAN | ENDORSEMENT_PK | 1 | | 0 (0)| 00:00:01 |
|* 12 | TABLE ACCESS BY INDEX ROWID | ROLE | 3 | 135 | 6 (0)| 00:00:01 |
|* 13 | INDEX RANGE SCAN | TC_ROLE66 | 62 | | 3 (0)| 00:00:01 |
|* 14 | INDEX RANGE SCAN | IDX_PROPERTY_TEST02 | 1 | 52 | 3 (0)| 00:00:01 |
|* 15 | INDEX RANGE SCAN | IDX_PROPERTY_TEST02 | 1 | 52 | 3 (0)| 00:00:01 |
|* 16 | INDEX RANGE SCAN | IDX_PROPERTY_TEST02 | 1 | 52 | 3 (0)| 00:00:01 |
|* 17 | INDEX RANGE SCAN | IDX_PROPERTY_TEST02 | 1 | 52 | 3 (0)| 00:00:01 |
-----------------------------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
7 - filter("P"."POLICYSTATUS"='$$900001103001' OR "E"."ENDORSEMENTSTATUS"='$$900002106001' AND
"E"."ISSUEDATE">TIMESTAMP' 2016-04-11 00:00:00')
9 - filter("P"."PRODUCTCODE"='00070002' AND ("P"."UNIQUECODE" LIKE '013100%' OR
"P"."UNIQUECODE" LIKE '011000%') AND "P"."CURRENTFLAG"='Y')
11 - access("P"."ENDORSEMENTID"="E"."ENDORSEMENTID"(+))
12 - filter("R"."KIND"='INSURANCECERTIFICATELIST')
13 - access("P"."TOPACTUALID"="R"."TOPACTUALID")
14 - access("R"."ACTUALID"="PRO4"."PARENTACTUALID" AND "R"."TOPACTUALID"="PRO4"."TOPACTUALID"
AND "R"."PARENTAGREEMENTID"="PRO4"."PARENTAGREEMENTID" AND
"R"."TOPAGREEMENTID"="PRO4"."TOPAGREEMENTID" AND "PRO4"."KIND"='CERTIFICATETYPE')
15 - access("R"."ACTUALID"="PRO3"."PARENTACTUALID" AND "R"."TOPACTUALID"="PRO3"."TOPACTUALID"
AND "R"."PARENTAGREEMENTID"="PRO3"."PARENTAGREEMENTID" AND
"R"."TOPAGREEMENTID"="PRO3"."TOPAGREEMENTID" AND "PRO3"."KIND"='PERSONSEX')
16 - access("R"."ACTUALID"="PRO2"."PARENTACTUALID" AND "R"."TOPACTUALID"="PRO2"."TOPACTUALID"
AND "R"."PARENTAGREEMENTID"="PRO2"."PARENTAGREEMENTID" AND
"R"."TOPAGREEMENTID"="PRO2"."TOPAGREEMENTID" AND "PRO2"."KIND"='CUSTOMERNAME')
17 - access("R"."ACTUALID"="PRO5"."PARENTACTUALID" AND "R"."TOPACTUALID"="PRO5"."TOPACTUALID"
AND "R"."PARENTAGREEMENTID"="PRO5"."PARENTAGREEMENTID" AND
"R"."TOPAGREEMENTID"="PRO5"."TOPAGREEMENTID" AND "PRO5"."KIND"='CERTIFICATECODE')
filter("PRO5"."VALUE" IS NOT NULL)
优化后
建立索引后,sql从原来的450s降低到20s,buffers 消耗也显著降低。
当执行计划中出现BITMAP CONVERSION TO ROWIDS关键字时,需要注意了。的更多相关文章
- SQL Server 2000中的并行处理和执行计划中的位图运算符
SQL Server 2000中的并行处理和执行计划中的位图运算符 摘抄自:SQLServer 2000并行处理和位图简介 刘志斌 并行查询介绍Degree of Parallelism(并行度) 一 ...
- 浅析SQL SERVER执行计划中的各类怪相
在查看执行计划或调优过程中,执行计划里面有些现象总会让人有些疑惑不解: 1:为什么同一条SQL语句有时候会走索引查找,有时候SQL脚本又不走索引查找,反而走全表扫描? 2:同一条SQL语句,查询条件的 ...
- [转载] EXPLAIN执行计划中要重点关注哪些要素
原文: https://mp.weixin.qq.com/s?__biz=MjM5NzAzMTY4NQ==&mid=400738936&idx=1&sn=2910b4119b9 ...
- SQL Server 执行计划中的扫描方式举例说明
SQL Server 执行计划中的扫描方式举例说明 原文地址:http://www.cnblogs.com/zihunqingxin/p/3201155.html 1.执行计划使用方式 选中需要执行的 ...
- 执行计划中常见index访问方式(转)
近期有朋友对于单个表上的index各种情况比较模糊,这里对于单个表上,单个index出现的大多数情况进行了总结性测试,给出了测试结果,至于为什么出现这样的试验结果未做过多解释,给读者留下思考的空间.本 ...
- MySQL 执行计划中Extra(Using where,Using index,Using index condition,Using index,Using where)的浅析
关于如何理解MySQL执行计划中Extra列的Using where.Using Index.Using index condition,Using index,Using where这四者的区别 ...
- 解读EXPLAIN执行计划中的key_len(转)
原文:http://imysql.com/2015/10/20/mysql-faq-key-len-in-explain.shtml 导读 EXPLAIN中的key_len一列表示什么意思,该如何解读 ...
- EXPLAIN执行计划中要重点关注哪些要素(叶金荣)
原文:http://mp.weixin.qq.com/s/CDKN_nPcIjzA_U5-xwAE5w 导读 EXPLAIN的结果中,有哪些关键信息值得注意呢? MySQL的EXPLAIN当然和ORA ...
- EXPLAIN执行计划中要重点关注哪些要素
MySQL的EXPLAIN当然和ORACLE的没法比,不过我们从它输出的结果中,也可以得到很多有用的信息. 总的来说,我们只需要关注结果中的几列: 列名 备注 type 本次查询表联接类型,从这里可以 ...
随机推荐
- ubuntu 怎么格式化U盘?(转载)
转自:http://3168247.blog.51cto.com/3158247/605654 图形的话装一个gparted,找那个/dev/sdb,右击选择格式化,最后点“应用”.命令行:原则是先卸 ...
- Swift4 基础
创建: 2018/02/17 完成: 2018/02/19 更新: 2018/02/25 补充参照型只有类的实例和闭包 更新: 2018/03/03 加红加粗for-in注意事项, 常量不用也不能声明 ...
- 51nod 1119 机器人走方格 V2 【组合数学】
挺水的但是我好久没写组合数了- 用这样一个思想,在1~m列中,考虑每一列上升几格,相当于把n-1个苹果放进m个篮子里,可以为空,问有几种方案. 这个就是一个组合数学经典问题了,考虑n个苹果放进m个篮子 ...
- springboot(八) 嵌入式Servlet容器自动配置原理和容器启动原理
1.嵌入式Servlet容器自动配置原理 1.1 在spring-boot-autoconfigure-1.5.9.RELEASE.jar => springboot自动配置依赖 jar包下,E ...
- Word排版技巧
点击打开链接 # 整体布局 ## 页面布局 如果是新建一个Word文件,这里「页面布局」一般不用设置了: 文字方向:从左到右: 页边距:普通(日常使用建议用适中或窄,节约用纸,提交的论文报告什么才用普 ...
- DP Codeforces Round #260 (Div. 1) A. Boredom
题目传送门 /* 题意:选择a[k]然后a[k]-1和a[k]+1的全部删除,得到点数a[k],问最大点数 DP:状态转移方程:dp[i] = max (dp[i-1], dp[i-2] + (ll) ...
- 水题 Codeforces Round #285 (Div. 2) C. Misha and Forest
题目传送门 /* 题意:给出无向无环图,每一个点的度数和相邻点的异或和(a^b^c^....) 图论/位运算:其实这题很简单.类似拓扑排序,先把度数为1的先入对,每一次少一个度数 关键在于更新异或和, ...
- PWA之serviceWorker应用
1.serviceWorker介绍service worker是一段运行在浏览器后台的JavaScript脚本,在页面中注册并安装成功后,它可以拦截和处理网络请求,实现缓存资源并可在离线时响应用户的请 ...
- 不通过getElementByName实现获取表单数据 (document.form表单的name值.input输入框的name值)
function update() { //document.form表单的name值.input输入框的name值 var username = document.form1.username; v ...
- jQuery幸运大转盘_jQuery+PHP抽奖程序
http://www.thinkphp.cn/code/1153.html 网上转盘抽奖程序大多是flash完成的,而本文使用jQuery和PHP来实现转盘抽奖程序. 若是想看更多js特效.网站源码. ...