People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input

Each input file contains one test case which occupies a line containing the three decimal color values.

Output

For each test case you should output the Mars RGB value in the following format: first output "#", then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a "0" to the left.

Sample Input

15 43 71

Sample Output

#123456
 #include<cstdio>
#include<iostream>
using namespace std;
void radix(int n){
int a, b;
a = n / ;
b = n % ;
if(a >= )
printf("%c", 'A' + a - );
else
printf("%c", '' + a);
if(b >= )
printf("%c", 'A' + b - );
else
printf("%c", '' + b);
} int main(){
int r, g, b;
scanf("%d%d%d", &r, &g, &b);
printf("#");
radix(r);
radix(g);
radix(b);
cin >> r;
return ; }

仍然是进制转换问题。为了方便输出0-9、A、B、C,可以将这13个字符存在字符数组中,建立0-12的对应关系。

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