Java for LeetCode 165 Compare Version Numbers

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37
解题思路：

先进行split，然后转为int比较即可，JAVA实现如下：

    static public int compareVersion(String version1, String version2) {
        String[] s1=version1.split("\\.");
        String[] s2=version2.split("\\.");
        int[] num1=new int[Math.max(s1.length, s2.length)];
        int[] num2=new int[Math.max(s1.length, s2.length)];
        for(int i=0;i<s1.length;i++)
        	num1[i]= Integer.valueOf(s1[i]);
        for(int i=0;i<s2.length;i++)
        	num2[i]= Integer.valueOf(s2[i]);
        for(int i=0;i<num1.length;i++){
        	if(num1[i]>num2[i])
        		return 1;
        	else if(num1[i]<num2[i])
        		return -1;
        }
        return 0;
    }