2014-05-01 01:32

题目链接

原题:

Given a linked list where apart from the next pointer, every node also has a pointer named random which can point to any other node in the linked list. Make a copy of the linked list.

题目:给定一个单链表,每个链表除了next指针以外,还有一个random指针,随机地指向nullptr或者链表中的某个节点。请设计算法完成一份链表的硬拷贝。

解法:Leetcode上有相关题目,请看题解LeetCode - Copy List with Random Pointer

代码:

 // http://www.careercup.com/question?id=5412018236424192
#include <unordered_map>
using namespace std; struct RandomListNode {
int label;
RandomListNode *next, *random;
RandomListNode(int x) : label(x), next(NULL), random(NULL) {};
}; class Solution {
public:
RandomListNode *copyRandomList(RandomListNode *head) {
// IMPORTANT: Please reset any member data you declared, as
// the same Solution instance will be reused for each test case.
int n; if(nullptr == head){
return nullptr;
} n = ;
RandomListNode *ptr; ptr = head;
while(ptr != nullptr){
++n;
mri[ptr] = n;
ptr = ptr->next;
} RandomListNode *root, *tail;
ptr = head; int i = ;
tail = root = nullptr;
while(ptr != nullptr){
++i;
if (root == nullptr) {
root = tail = new RandomListNode(ptr->label);
} else {
tail->next = new RandomListNode(ptr->label);
tail = tail->next;
}
mir[i] = tail;
ptr = ptr->next;
} RandomListNode *p1, *p2; p1 = head;
p2 = root;
while(p1 != nullptr){
if(p1->random != nullptr){
p2->random = mir[mri[p1->random]];
}
p1 = p1->next;
p2 = p2->next;
} mir.clear();
mri.clear(); return root;
}
private:
unordered_map<RandomListNode *, int> mri;
unordered_map<int, RandomListNode *> mir;
};

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