static ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) {
        ListNode *temp = );
        ListNode *head = temp;
        if (l1 == NULL && l2 == NULL)
            return head;
        while (l1 != NULL && l2 != NULL) {
            if (l1->val <= l2->val) {
                temp->next = new ListNode(l1->val);
                temp = temp->next;
                l1 = l1->next;
            } else {
                temp->next = new ListNode(l2->val);
                temp = temp->next;
                l2 = l2->next;
            }
        }
        if (l1 == NULL && l2 != NULL)
            temp->next = l2;
        else if (l2 == NULL && l1 != NULL)
            temp->next = l1;
        return head->next;
    }

Leetcode--Merge Two Sorted Lists的更多相关文章

  1. [LeetCode] Merge k Sorted Lists 合并k个有序链表

    Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 这 ...

  2. [LeetCode] Merge Two Sorted Lists 混合插入有序链表

    Merge two sorted linked lists and return it as a new list. The new list should be made by splicing t ...

  3. LeetCode: Merge Two Sorted Lists 解题报告

    Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list shoul ...

  4. LeetCode: Merge k Sorted Lists 解题报告

    Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and descr ...

  5. [Leetcode] Merge k sorted lists 合并k个已排序的链表

    Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思 ...

  6. LeetCode:Merge k Sorted Lists

    题目链接 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexi ...

  7. LeetCode——Merge k Sorted Lists

    Discription: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its ...

  8. leetcode:Merge Two Sorted Lists(有序链表的归并)

    Merge two sorted linked lists and return it as a new list. The new list should be made by splicing t ...

  9. leetcode -- Merge k Sorted Lists add code

    Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. [ ...

  10. LeetCode Merge k Sorted Lists (链表)

    题意 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity ...

随机推荐

  1. Eclipse断点调试方法

    1. 条件断点 断点大家都比较熟悉,在Eclipse Java 编辑区的行头双击就会得到一个断点,代码会运行到此处时停止. 条件断点,顾名思义就是一个有一定条件的断点,只有满足了用户设置的条件,代码才 ...

  2. 爱挑剔的acm程序员 acmer

    2015-9-2 acmer敢于承认自己的错误,并积极改进.自信.有些酷爱运动,各个方面都很优秀:有些则认为出去“玩”就不是玩,有自己的小世界,玩电脑才是最爱. 2015-9-1 acmer都很聪明, ...

  3. (转)漫谈SOA(面向服务架构)

    http://blog.csdn.net/luohuacanyue/article/details/12521699 面向服务架构的思想在整个软件的架构中已经不是什么新鲜的东西.我简单的认为服务化是模 ...

  4. django 富文本展示 以及 post提交出错

    1.富文本转义 使用 {{ content.record.content | safe }} 2.post提交报错 页面表单内追加 <form id="f"action=&q ...

  5. jQuery的deferred对象学习

    #copy { background-color: lightgreen; padding: 15px; margin: 10px } 一.deferred对象简介 deferred对象是jquery ...

  6. EF事务嵌套

    EF中采用的是数据上下文DbContext,当针对数据库的所有操作共用一个数据上下文的时候,会使用同一个连接对象,因此连接打开一次,最后Save的时候关闭连接,避免了频繁的创建连接对象打开关闭,这在一 ...

  7. python utf-8 配置

    环境:centos6.5,python 2.6 源码文档使用utf-8 #!/usr/bin/python # -*- coding: UTF-8 -*- 字符串默认用utf-8(不用在前面加u了) ...

  8. oracle 自增ID

    drop sequence SEQ_sys_dictionary; create sequence SEQ_sys_dictionary INCREMENT BY START WITH ; creat ...

  9. 软件工程(C编码实践篇)总结

    陆伟丹 + 原创作品转载请注明出处 + <软件工程(C编码实践篇)>MOOC课程http://mooc.study.163.com/course/USTC-1000002006 对软件工程 ...

  10. what is difference in (int)a,(int&)a,&a,int(&a) ?

    This interview question come from a famous communication firm of china. : ) #include <iostream> ...