本次课我主要学习了二维数组和集合的部分内容。

在二维数组的部分中,我主要学习了二维数组的定义方法:int [,] array=new int [4,2];做了一个小练习:用二维数组打印自己的姓氏。

string[,] a = new string[11, 9]
{
{" "," "," "," ","■"," "," "," "," "},
{" "," "," "," ","■"," "," "," "," "},
{" ","■","■","■","■","■","■","■"," "},
{" "," "," ","■","■","■"," "," "," "},
{" ","■","■"," ","■"," ","■","■"," "},
{" "," ","■","■","■","■","■"," "," "},
{" "," "," "," "," ","■"," "," "," "},
{"■","■","■","■","■","■","■","■","■"},
{" "," "," "," ","■"," "," "," "," "},
{" "," "," ","■","■"," "," "," "," "},
{" "," "," "," ","■"," "," "," "," "},
};
for (int i = 0; i < 11; i++)
{
for (int j = 0; j < 9; j++)
{
Console.Write(a[i, j]);
}
Console.WriteLine();
}
Console.ReadLine();

然后,我学习了一个split() 分离

例:

一次性接收姓名、年龄、工作单位
Console.Write("请输入您的姓名、年龄、工作单位(**-**-**):");
string quan = Console.ReadLine();
string[] array = quan.Split('-');
for (int i = 0; i < array.Length; i++)
{
Console.WriteLine(array[i]);
}
Console.ReadLine();

学习完二维数组的内容,我开始学习了集合的部分内容。

ArrayList al = new ArrayList();//初始化
al.Add(5);
al.Add(3);
al.Add(6);
al.Add(4);
al.Add(1);
al.Add(2);
al.Add("2");
al.Add("hello");
al.Add(true);
al[3] = "你好";
al.Clear(); 移除所有元素
ArrayList al1 = new ArrayList();

al1 = (ArrayList)al.Clone();//克隆
//判断是否包含
Console.WriteLine(al1.Contains("2"));
//获取第一次出现该元素的索引号
Console.WriteLine(al1.IndexOf(11));
//获取最后一次出现该元素的索引号
Console.WriteLine(al1.LastIndexOf(2));
//插入某个索引位置某个元素
al.Insert(2,"Hello");

//移除某个第一次出现的元素
al.Remove("hello");
//移除某个索引位置的元素
al.RemoveAt(3);

al.Sort();//排序 ,升序
al.Reverse();//翻转整个集合
Console.WriteLine(al[2]);
Console.WriteLine(al.Count);
Console.ReadLine();

在学习了集合的基本知识之后,我做了一个综合性的题目来对我所学习的内容加以巩固。

例:输入班级人数,输入每个人的姓名、语数英成绩进入集合;求语文的总分,数学的平均分,英语的最高分的人的姓名及所有科目的分数(冒泡排序)

0     姓名  4   8  12
    1 语文成绩5   9  13
    2 数学成绩6 10  14
    3 英语成绩7 11  15

Console.Write("请输入班级人数:");
int n = int.Parse(Console.ReadLine());
double yu = ;
double shu = ;
ArrayList al = new ArrayList();
for (int i = ; i < n; i++)
{
Console.Write("请输入第{0}个人的姓名:",i+);
al.Add(Console.ReadLine());
Console.Write("请输入第{0}个人的语文成绩:",i+);
al.Add(double.Parse(Console.ReadLine()));
yu += double.Parse(al[al.Count - ].ToString());
Console.Write("请输入第{0}个人的数学成绩:", i + );
al.Add(double.Parse(Console.ReadLine()));
shu += double.Parse(al[al.Count - ].ToString());
Console.Write("请输入第{0}个人的英语成绩:", i + );
al.Add(double.Parse(Console.ReadLine()));
}
Console.WriteLine("所有信息输入完毕,请按回车键继续!");
Console.ReadLine();
Console.WriteLine("语文的总分是:"+yu);
Console.WriteLine("数学的平均分是:"+(shu/n)); for (int i = ; i < *n-; i+=)
{
for (int j = i; j < * n - ; j += )
{
if (double.Parse(al[i].ToString()) < double.Parse(al[j + ].ToString()))
{
//换姓名
object zhong = al[i - ];
al[i - ] = al[j + ];
al[j + ] = zhong;
//换语文
zhong = al[i - ];
al[i - ] = al[j + ];
al[j + ] = zhong;
//换数学
zhong = al[i - ];
al[i - ] = al[j + ];
al[j + ] = zhong;
//换英语
zhong = al[i];
al[i] = al[j + ];
al[j + ] = zhong;
}
}
}
Console.WriteLine("英语最高分的学生是{0},英语分数是{1},语文分数是{2},数学分数{3}",al[],al[],al[],al[]);
Console.ReadLine();

C# 二维数组和集合的更多相关文章

  1. C#(二维数组/集合)

    一.二维数组int [,] array = new int[5,3];//有五个一维数组,每一个一维数组有3个元素 /打印出来一个“王”这个字string[,] wang = new string[, ...

  2. PHP 如何获取二维数组中某个key的集合(高性能查找)

    分享下PHP 获取二维数组中某个key的集合的方法. 具体是这样的,如下一个二维数组,是从库中读取出来的. 代码: $user = array( 0 => array( 'id' => 1 ...

  3. PHP 获取二维数组中某个key的集合

    本文为代码分享,也是在工作中看到一些“大牛”的代码,做做分享. 具体是这样的,如下一个二维数组,是从库中读取出来的. 代码清单: $user = array( 0 => array( 'id'  ...

  4. 二维数组,锯齿数组和集合 C# 一维数组、二维数组(矩形数组)、交错数组(锯齿数组)的使用 C# 数组、多维数组(矩形数组)、锯齿数组(交叉数组)

    二维数组,锯齿数组和集合 一.二维数组 二维数组:一维数组----豆角二维数组----表格 定义:1.一维数组:数据类型[] 数组变量名 = new 数据类型[数组长度];数据类型[] 数组变量名 = ...

  5. PHP使用array_filter查找二维数组中符合字段和字段值的数据集合

    1.方法: /** * 获取符合字段和字段值的数组集合 * @param array $data 待过滤数组 * @param string $field 要查找的字段 * @param $value ...

  6. php获取二维数组中某一列的值集合

    $result //二维数组$uid_list = array_column($result, 'uid');

  7. ***php解析JSON二维数组字符串(json_decode函数第二个参数True和False的区别)

    客户端的请求体中的数据:[{"msg_id": 1, "msg_status": "HAS_READ" }, { "msg_id& ...

  8. Android 在资源文件(res/strings.xml)定义一维数组,间接定义二维数组

    经常我们会在资源文件(res/strings.xml)定义字符串,一维数组,那定义二维数组?直接定义二维数组没找到,可以间接定义. 其实很简单,看过用过一次就可以记住了,一维数组估计大家经常用到,但是 ...

  9. 数组(Array),二维数组,三维数组

    数组(Array):相同类型数据的集合就叫做数组. (一)定义数组的方法: A) type[] 变量名 = new type[数组中元素的个数] 例如: int[] a = new int[10] ; ...

随机推荐

  1. HDU 5886 Tower Defence

    树的直径. 比赛的时候想着先树$dp$处理子树上的最长链和次长链,然后再从上到下进行一次$dfs$统计答案,和$CCPC$网络赛那个树$dp$一样,肯定是可以写的,但会很烦.......后来写崩了. ...

  2. ModelState.IsValid一直为false的原因

    一,问题:ModelState.IsValid一直为false 二,解决方法和原因, 由于这个方法中传过来的RegisterForm模型的字段,某一个为空值,则会造成这个验证验证为false,去注释掉 ...

  3. [DP之普通系列]

    noip快要来了 要练练dp 难度也挺接近 还是挺好的 [Usaco2013 Nov]Pogo-Cow 这一道题要下一段大于这一段 所以的话我们就要记录每一段的状态 F[i,j]=F[j,k]+A[i ...

  4. Java 并发 线程的生命周期

    Java 并发 线程的生命周期 @author ixenos 线程的生命周期 线程状态: a)     New 新建 b)     Runnable 可运行 c)     Running 运行 (调用 ...

  5. 关于css起名

    作者:词晖链接:https://www.zhihu.com/question/19586885/answer/48933504来源:知乎著作权归作者所有,转载请联系作者获得授权. CSS书写顺序 1. ...

  6. 关于scanf的返回值

    今天写一个小程序时误用while(scanf("%d",&b)!=a),以为scanf的返回值就是输入的值. 其实真相是: scanf返回接收到的变量值的个数. int a ...

  7. mysql近几天的查询

    今天:select*from table1 where to_days(时间字段名)=to_days(now()); 昨天:select*from table1 where to_days(now() ...

  8. java登录密码效验

    密码校验需求: 1) 密码控制只能输入字母.数字.特殊符号(~!@#$%^&*()_+[]{}|\;:'",./<>?)2) 长度 6-16 位,必须包括字母.数字.特殊 ...

  9. LeetCode 之 Triangle

    Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent n ...

  10. 第八十九节,html5+css3pc端固定布局,热门旅游取,标题介绍区,旅游项目区

    html5+css3pc端固定布局,热门旅游取,标题介绍区,旅游项目区 样式: html代码: <!--主体--> <section class="zhu-ti" ...