LeetCode #139. Word Break C#
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words.
For example, given s = "leetcode", dict = ["leet", "code"].
Return true because "leetcode" can be segmented as "leet code".
Solution:
Need to use DP because derictly loop through the string may not return the correct answer.
Test case: s="aaaaaaa", dict = ["aaa", "aaaa"]
Two solutions:
First Dynamic programming:
dp[0] = true;// always true, because empty string can always add space to it.
dp[1] = dp[0]&&dict.Contains(s.Substring(0, 1);
dp[2] =( dp[1]&&dict.Contains(s.Substring(1,1))) ||(dp[0]&& dict.Contains(s.Substring(0,2)));
so need to loop through dp[j]&&wordDict.Contains(s.Substring(j,i-j)) untill dp[i] is true where j from 0 to i;
public class Solution {
public bool WordBreak(string s, ISet<string> wordDict)
{
ISet<int> set = new HashSet<int>();
if(string.IsNullOrEmpty(s))
{
return true;
}
int l = s.Length;
bool[] dp = new bool[l+];
dp[] = true;
for(int i=; i<l+; i++)
{
for(int j=; j<i; j++)
{
dp[i]=dp[j]&&wordDict.Contains(s.Substring(j,i-j));
if(dp[i])
{
break;
}
}
}
return dp[l];
}
}
Second DFS:
Use recursion in Dfs to mark the indexes those already looped through and returned false;
public class Solution {
public bool WordBreak(string s, ISet<string> wordDict)
{
ISet<int> set = new HashSet<int>();
return Dfs(s, , wordDict, set);
}
private bool Dfs(string s, int index, ISet<string> dict, ISet<int> set)
{
// base case
if (index == s.Length) return true;
// check memory
if (set.Contains(index)) return false;
// recursion
for (int i = index + ; i <= s.Length; i++)
{
String t = s.Substring(index, i-index);
if (dict.Contains(t))
if (Dfs(s, i, dict, set))
return true;
else
set.Add(i);
}
set.Add(index);
return false;
}
}
LeetCode #139. Word Break C#的更多相关文章
- [LeetCode] 139. Word Break 单词拆分
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine ...
- leetcode 139. Word Break 、140. Word Break II
139. Word Break 字符串能否通过划分成词典中的一个或多个单词. 使用动态规划,dp[i]表示当前以第i个位置(在字符串中实际上是i-1)结尾的字符串能否划分成词典中的单词. j表示的是以 ...
- Leetcode#139 Word Break
原题地址 与Word Break II(参见这篇文章)相比,只需要判断是否可行,不需要构造解,简单一些. 依然是动态规划. 代码: bool wordBreak(string s, unordered ...
- LeetCode 139. Word Break单词拆分 (C++)
题目: Given a non-empty string s and a dictionary wordDict containing a list of non-emptywords, determ ...
- leetcode 139. Word Break ----- java
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separa ...
- [leetcode]139. Word Break单词能否拆分
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine ...
- [LeetCode] 139 Word Break(BFS统计层数的方法)
原题地址: https://leetcode.com/problems/word-break/description/ 题目: Given a non-empty string s and a dic ...
- [LeetCode] 139. Word Break 拆分词句
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine ...
- Java for LeetCode 139 Word Break
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separa ...
随机推荐
- Chrome新的语言API,让您的浏览器说话
还记得曾经那个能识别语音的API吗?当时一直在想,如果能让浏览器替我念出文字就好了.现在chrome的最新版本Version 33 中您只要按F12然后在console里面输入这段代码,您就能听到浏览 ...
- CentOS-6.5x64:SSH安装配置
1.CentOS 默认已经安装了 OpenSSH 2.vim /etc/ssh/sshd_config Port: SSH的监听端口 默认为22,设置为[Port 22] Protocol:SSH允许 ...
- 【stanford C++】字符串(String)与流(Stream)
字符串(String)与流(Stream) 一.C++中字符串(String) 字符串(String):就是(可能是空的)字符序列. C++中的字符串在概念上和Java中的字符串类似. C++字符串用 ...
- jquery代码实现简单的五星评价功能!
实现: 1,鼠标移动到第三个星星,则一二三星星变亮,后两个变暗 2,鼠标点击某个星星后,可以继续选择,但拿开后星星会定格住你点击的位置 <script type="text/javas ...
- Hexo+NextT基本设置【3】
该系列博客列表请访问:http://www.cnblogs.com/penglei-it/category/934299.html 摘要 或许在你看到我这篇我文章之前,你已经成功的通过Git ...
- Thymeleaf 笔记
th:each=”aname : ${namelist}” th:if=”${name} == ‘SERVICED’” 页面使用Map集合 <div th:each="osl : ${ ...
- 在VS中配置并测试opencv
什么是opencv? opencv是一个计算机视觉库.它目前有两个分支2.4.X和3.X,2.4.X版本是经典版本,网上的教程资源大多是关于它的,所以推荐使用2.4.X. 它能帮我做什么? 这意味着你 ...
- 分享php工作中遇到的一些探究和技巧【2】
1 如何定义linux和window通用的文件分隔符号 DIRECTORY_SEPARATOR : 目录分隔符,是定义php的内置常量.在调试机器上,在windows我们习惯性的使用"\& ...
- Dos.ORM Select查询 自定义列
自定义列 .Select( p = >new{ test = p.id}) // 同sql 列名 as 新列名 如下是 自己在写代码的例子,查询,分页,where条件,排序 var where ...
- [HMLY]14.对iOS开发中使用MVVM的理解和使用(初级)
前言 MVVMDemo 之前几个月一直在学习react-native,它的组件化开发真的是很棒,控件和页面的组件化在开发中可以很好的复用,节省开发时间.在那个时候还不知道react-native开发用 ...