先算出目标状态,然后拿当前状态与目标状态对比,即可算出答案

#include<cstdio>
#include<cmath>
#include<cstring>
#include<algorithm>
using namespace std; const int maxn=+;
int a[maxn];
int b[maxn]; int main()
{
int n;
scanf("%d",&n);
for(int i=;i<=n;i++) scanf("%d",&a[i]); sort(a+,a++n);
int sum=;
for(int i=;i<=n;i++) sum=sum+a[i]; int ave=sum/n;
for(int i=;i<=n;i++) b[i]=ave; int MOD=sum%n;
for(int i=n;i>=n-MOD+;i--) b[i]++; // for(int i=1;i<=n;i++) printf("%d ",b[i]);
int ans=;
for(int i=;i<=n;i++)
ans=ans+max(,a[i]-b[i]); printf("%d\n",ans);
return ;
}

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