Description:

Given a binary tree, return all root-to-leaf paths.

For example, given the following binary tree:

   1
/ \
2 3
\
5

All root-to-leaf paths are:

["1->2->5", "1->3"]

Code:

  void allPath(TreeNode*root, vector<string>&result, vector<int>&path)
{
if (root==NULL)
return ;
path.push_back(root->val);
if (root->left==NULL && root->right==NULL)
{
//注意这里要用ostringstream将字符串写到流中去,然后用str()函数返回字符串
ostringstream sstr;
for (int i = ; i < path.size()-; ++i)
sstr << path[i]<<"->";
sstr<<path[path.size()-];
result.push_back(sstr.str());
}
else
{
if (root->left)
allPath(root->left, result, path);
if (root->right)
allPath(root->right, result, path);
}
path.pop_back();
}
vector<string> binaryTreePaths(TreeNode* root) {
vector<string>result;
vector<int>path;
allPath(root, result,path);
return result;
}

Binary Tree Paths的更多相关文章

  1. [LintCode] Binary Tree Paths 二叉树路径

    Given a binary tree, return all root-to-leaf paths.Example Given the following binary tree: 1 /   \2 ...

  2. LintCode Binary Tree Paths

    Binary Tree Paths Given a binary tree, return all root-to-leaf paths. Given the following binary tre ...

  3. 【LeetCode】257. Binary Tree Paths

    Binary Tree Paths Given a binary tree, return all root-to-leaf paths. For example, given the followi ...

  4. &lt;LeetCode OJ&gt; 257. Binary Tree Paths

    257. Binary Tree Paths Total Accepted: 29282 Total Submissions: 113527 Difficulty: Easy Given a bina ...

  5. LeetCode_257. Binary Tree Paths

    257. Binary Tree Paths Easy Given a binary tree, return all root-to-leaf paths. Note: A leaf is a no ...

  6. [LeetCode] Binary Tree Paths 二叉树路径

    Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 ...

  7. leetcode : Binary Tree Paths

    Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 ...

  8. Leetcode 257. Binary Tree Paths

    Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 ...

  9. (easy)LeetCode 257.Binary Tree Paths

    Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: 1 ...

随机推荐

  1. rtc关机闹钟7 jni层 com_android_server_AlarmManagerService

    frameworks/base/services/core/jni/com_android_server_AlarmManagerService.cpp int AlarmImplAlarmDrive ...

  2. YTU 2989: 顺序表基本运算(线性表)

    2989: 顺序表基本运算(线性表) 时间限制: 1 Sec  内存限制: 128 MB 提交: 1  解决: 1 题目描述 编写一个程序,实现顺序表的各种基本运算(假设顺序表的元素类型为char), ...

  3. 发现一个jq的问题

    用jq对checkbox的checked属性进行操作时,使用$(‘#id’).attr(‘checked’, true);竟然无效,改成$(‘#id’).prop(‘checked’, true);才 ...

  4. (POJ2635)The Embarrassed Cryptographer(大数取模)

    The Embarrassed Cryptographer Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 13041 Accep ...

  5. linux内核2.4.x网络接口分析层次图

    http://blog.csdn.net/wswifth/article/details/5108744 今天大概分写了下<Linux内核2.4.x的网络接口源码的结构[转]>中的结构层次 ...

  6. Resilio(BtSync)搭建

    Resilio(原名:BtSync)介绍 同步是使用PC和Mac,NAS,甚至服务器之间传输文件的最好方法.创建自己的私有云.连接设备和同步文件安全,不发送他们在第三方服务器.我们不限制你的速度和存储 ...

  7. Linux下统计出现次数最多的指定字段值

    假设桌面上有一个叫“data.txt”的文本,内容如下: {id='xxx' info='xxx' kk='xxx' target='111111' dd='xxx'}{id='xxx' info=' ...

  8. 浅谈Apache性能调优

    做了很多WEB系统性能测试,都知道了解测试环境,服务器硬件配置,web服务器参数配置是我们开始测试前首先要做的事情. 针对并发数量来说,不同数量级的用户并发,需求的服务器和web服务参数肯定是不同的. ...

  9. Codeforces Round #373 (Div. 2) A

    Description Every summer Vitya comes to visit his grandmother in the countryside. This summer, he go ...

  10. 2016年10月22日 星期六 --出埃及记 Exodus 19:6

    2016年10月22日 星期六 --出埃及记 Exodus 19:6 you will be for me a kingdom of priests and a holy nation.' These ...