Given a binary tree, flatten it to a linked list in-place.

For example,
Given

         1
/ \
2 5
/ \ \
3 4 6

The flattened tree should look like:

   1
\
2
\
3
\
4
\
5
\
6

这道题就是将数变为只有右节点的树。

递归,不是很难。

递归的时候求出左节点的最右孩子即可。

/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public void flatten(TreeNode root) {
if( root == null)
return ;
else if( root.left == null )
flatten(root.right);
else{
TreeNode node = root.right;
TreeNode node2 = getRight(root.left);
root.right = root.left;
root.left = null;
node2.right = node;
flatten(root.right);
} }
public TreeNode getRight(TreeNode root ){
while( root.right != null)
root = root.right; return root; }
}

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