https://codeforces.com/contest/1080/problem/E

比赛时候一个多小时码不出来。。。

来看遇到的困难:

1.没有能用的随机unsignedlonglong函数

来一个可以A题的:

ull splitmix64(ull x) {
x += 0x9e3779b97f4a7c15;
x = (x ^ (x >> )) * 0xbf58476d1ce4e5b9;
x = (x ^ (x >> )) * 0x94d049bb133111eb;
return x ^ (x >> );
}
ull rd()
{
static ull x=splitmix64(chrono::steady_clock::now().time_since_epoch().count());
return splitmix64(x=x*6364136223846793005ull+1442695040888963407ull);
}

2.不会马拉车

以后学。。以下代码的马拉车(calc函数)是网上找的

 #include<cstdio>
#include<algorithm>
#include<cstring>
#include<vector>
#include<chrono>
#include<cstdlib>
using namespace std;
#define fi first
#define se second
#define mp make_pair
#define pb push_back
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> pii; ull cpy[];
int rad[]; ull splitmix64(ull x) {
x += 0x9e3779b97f4a7c15;
x = (x ^ (x >> )) * 0xbf58476d1ce4e5b9;
x = (x ^ (x >> )) * 0x94d049bb133111eb;
return x ^ (x >> );
}
ull rd()
{
static ull x=splitmix64(chrono::steady_clock::now().time_since_epoch().count());
return splitmix64(x=x*6364136223846793005ull+1442695040888963407ull);
} void manacher(ull str[], int rad[], int len) {
for (int i=,j=,k; i < len; i+=k,j-=k) {
while (str[i-j-] == str[i+j+]) ++j;
rad[i] = j;
for (k=; k<=j && rad[i-k]!=rad[i]-k; ++k) {
rad[i+k] = min(rad[i-k], rad[i]-k);
}
}
} ll calc(const ull *seq,int len)
{
//for(int i=0;i<len;++i)
// printf("1t%llu\n",seq[i]);
ull t1,t2,t3;
while()
{
t1=rd();t2=rd();t3=rd();
if(t1==t2||t1==t3||t2==t3) continue;
for(int i=;i<len;++i)
if(t1==seq[i]||t2==seq[i]||t3==seq[i])
continue;
break;
}
cpy[] = t1, cpy[] = t2;
for (int i=,j=; j < len; i+=,++j) {
cpy[i] = seq[j];
cpy[i+] = t2;
}
len = len*+;
cpy[len-] = t3;
manacher(cpy, rad, len);
ll ret = ;
for (int i = ; i < len-; ++i) {
ret += (rad[i]+) / ;
}
//printf("2t%lld\n",ret);
return ret;
} ull bs,bss[]={,,,,,};
ull pwx[];
ull st[];int tp;
struct CharSet
{
int num[],odd;
ull hs;
void add(int c)
{
++num[c];
odd^=(<<c);
hs+=pwx[c];
}
void del(int c)
{
--num[c];
odd^=(<<c);
hs-=pwx[c];
}
void clear()
{
memset(num,,sizeof(num));
odd=;
hs=;
}
}cs[];
ll ans;
bool ok[];
int n,m;
int to[];
char s[][];
int main()
{
int i,j,l,r;
bs=bss[rd()%];
//printf("1t%llu\n",bs);
pwx[]=;
for(i=;i<=;++i)
pwx[i]=pwx[i-]*bs;
//n=250;m=250;
scanf("%d%d",&n,&m);
for(i=;i<=n;++i)
{
scanf("%s",s[i]+);
//for(j=1;j<=m;++j)
// s[i][j]=rand()%3+'a';
}
for(l=;l<=m;++l)
{
for(i=;i<=n;++i)
cs[i].clear();
for(r=l;r<=m;++r)
{
for(i=;i<=n;++i)
cs[i].add(s[i][r]-'a');
if((r-l+)&)
{
for(i=;i<=n;++i)
{
to[i]=__builtin_ffs(cs[i].odd)-;
cs[i].del(to[i]);
}
}
for(i=;i<=n;++i)
ok[i]=!cs[i].odd;
if((r-l+)&)
{
for(i=;i<=n;++i)
cs[i].add(to[i]);
}
//printf("3t%d %d\n",l,r);
//for(i=1;i<=n;++i)
// printf("4t%llu\n",cs[i].hs);
for(i=;i<=n;++i)
if(ok[i])
{
tp=;
j=i;st[++tp]=cs[i].hs;
while(j+<=n&&ok[j+])
{
++j;
st[++tp]=cs[j].hs;
}
ans+=calc(st+,tp);
i=j;
}
//printf("5t%lld\n",ans);
}
}
printf("%lld\n",ans);
return ;
}

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