字符串和整形数组的相互转化（JAVA程序）

 package te;
 public class StringConvert {
     static int[] a = {0,1,1,0,1,1,0,2};
     static String s = "0011223344";
     public static void main(String[] args) {
         StringConvert sc = new StringConvert();
         System.out.println(sc.intArray2Str(a));
         int[] b = sc.str2IntArray(s);
         for(int i=0; i<b.length; i++) {
             System.out.print(b[i]);
         }
     }

     String intArray2Str(int[] a) {

         int len = a.length;
         String str="";
         for(int i=0;i<len; i++) {
             str+=String.valueOf(a[i]);
         }
         return str;
     }

     int[] str2IntArray(String str) {
         int len = str.length();
         int[] a = new int[len];
         char[] c = str.toCharArray();
         for(int i=0; i<len; i++) {
             a[i] = c[i]-'0';
         }
         return a;
     }

 }

结果

01101102
0011223344

 package te;

 import java.util.regex.Matcher;
 import java.util.regex.Pattern;

 public class StringConvert {
     static int[] a = {0,1,1,0,1,1,0,2};
     static String s = "0011223340004";
     public static void main(String[] args) {
         StringConvert sc = new StringConvert();
         System.out.println(sc.intArray2Str(a));
         int[] b = sc.str2IntArray(s);
         for(int i=0; i<b.length; i++) {
             System.out.print(b[i]);
         }
         System.out.print('\n');
         sc.indexsof(s);
     }

     String intArray2Str(int[] a) {

         int len = a.length;
         String str="";
         for(int i=0;i<len; i++) {
             str+=String.valueOf(a[i]);
         }
         return str;
     }

     int[] str2IntArray(String str) {
         int len = str.length();
         int[] a = new int[len];
         char[] c = str.toCharArray();
         for(int i=0; i<len; i++) {
             a[i] = c[i]-'0';
         }
         return a;
     }
     int[] indexsof(String s) {

          Pattern p = Pattern.compile("[0]");
          Matcher m = p.matcher(s);
          while(m.find()) {
              System.out.println(m.start());
          }

         return null;

     }
 }

从一个字符串中找到符合要求字符串的所有位置